CODEWITHSUNDEEP
javascript
kratos
kratos

Reputation: 101

Avoid call function with a parameter call many times

I have this:

function myalert(x)
{
  alert("hey + " x)
}

i am calling a afunction with different parameters

myalert("A");
myalert("B");
myalert("C");
myalert("A");
myalert("B");
myalert("C");
myalert("A");
myalert("B");
myalert("C");

can I avoid that ugly repetition?

update=But what if 2 parameters? How will I make the "LIST" you are talking about? Example:

function myalert(x,y)
{
  alert(y + "hey + " x )
}

myalert("A", "X");
myalert("B", "X");

How can i make a list of this?

Upvotes: 1

Views: 58

Answers (3)

Wahid Bitar
Wahid Bitar

Reputation: 14094

myalert(['A', 'B', 'C']);

function myalert(dataArray)
{
  dataArray.forEach(function(e) {
    alert("hey " + x);
  });
}

Upvotes: 0

aksu
aksu

Reputation: 5235

Loop it. You can get function arguments using arguments and their count arguments.length.

function myalert()
{
  var count = arguments.length;
  for(var i = 0; count > i; i++) {
     alert("hey + " + arguments[i]);
  }
}

myalert('a', 'b', 'c'); // alerts a, alerts b, alerts c

Upvotes: 1

xdazz
xdazz

Reputation: 160863

Put all parameters in an array, then use a loop.

var params = ['A', 'B', 'C'];

for (var i = 0, l = parmas.length; i < l; i++) {
    myalert(params[i]);
}

or:

['A', 'B', 'C'].forEach(function(e) {
    myalert(e);
});

Upvotes: 0

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