Jeff
Jeff

Reputation: 2862

Regex & PHP - isolate src attribute from img tag

With PHP, how can I isolate the contents of the src attribute from $foo? The end result I'm looking for would give me just "http://example.com/img/image.jpg"

$foo = '<img class="foo bar test" title="test image" src="http://example.com/img/image.jpg" alt="test image" width="100" height="100" />';

Upvotes: 42

Views: 69498

Answers (11)

Harsh Patel
Harsh Patel

Reputation: 1334

<?php
    $html = '
        <img border="0" src="/images/image1.jpg" alt="Image" width="100" height="100" />
        <img border="0" src="/images/image2.jpg" alt="Image" width="100" height="100" />
        <img border="0" src="/images/image3.jpg" alt="Image" width="100" height="100" />
        ';
    
    $get_Img_Src = '/<img[^>]*src=([\'"])(?<src>.+?)\1[^>]*>/i'; //for get img src path only...
    
    preg_match_all($get_Img_Src, $html, $result); 
    if (!empty($result)) {
        echo $result['src'][0];
        echo $result['src'][1];
    }

for get img src path & alt text also then use below regex instead of above...

<img[^>]*src=(['"])(?.+?)\1[^>]alt=(['"])(?.+?)\2>

    $get_Img_Src = '/<img[^>]*src=([\'"])(?<src>.+?)\1[^>]*alt=([\'"])(?<alt>.+?)\2*>/i'; //for get img src path & alt text also
    
    preg_match_all($get_Img_Src, $html, $result); 
    if (!empty($result)) {
        echo $result['src'][0];
        echo $result['src'][1];
        echo $result['alt'][0];
        echo $result['alt'][1];
    }

I got idea of that great solution from here, PHP extract link from a href tag


For Extract Urls of specific domains only then try below regex

// for e.g. if you need to extract onlt urls of "test.com" 
// then you can do it as like below regex

<a[^>]+href=([\'"])(?<href>(https?:\/\/)?test\.com.* ?)\1[^>]*>

Additional Info

for get img src attributes that contain base64 encoded data, you can do it as like below. you can test it on here onlinephp.io

<?php
$html = '
    <p>test </p>
    <img border="0" src="/images/image1.jpg" alt="Image" width="100" height="100" />
    <img border="0" src="/images/image2.jpg" alt="Image" width="100" height="100" />
    <img border="0" src="/images/image3.jpg" alt="Image" width="100" height="100" />
    <img border="0" src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAJUAAAAfCAYAAADuiY/xAAAAGXRF..." alt="Base64 Image 1" width="100" height="100" />
    <img border="0" src="data:image/jpeg;base64,/9j/4AAQSkZJRgABAQEAAAAAAAAAAAAAAEAAQAAAQAAAQEAAEAAAD/..." alt="Base64 Image 2" width="100" height="100" />
    <h1>asas</h1>
    <img border="0" src="/images/image2.jpg" alt="Image" width="100" height="100" />
    <img border="0" src="http://test.com/images/image2.jpg" width="100" height="100" />
    <img src="data:image/gif;base64,R0lGODlhPQBEAP8A..." />
';

$get_Img_Src = '/<img[^>]*src=["\'](data:image\/[^;]+;base64[^"\']+)["\'][^>]*>/i'; // Regex to capture base64 image src

preg_match_all($get_Img_Src, $html, $result);

// Debugging step: print the entire result array
//echo "Full result:\n";
//print_r($result);

if (!empty($result[1])) {
    echo "Base64 matches found: " . count($result[1]) . PHP_EOL;
    $updated_html = $html;
    // Access the base64 data in the first capture group, i.e. $result[1]
    foreach ($result[1] as $index => $base64) {
        echo $base64 . PHP_EOL;  // Echo each base64 encoded image string
        // Replace the base64 string with the corresponding URL
       $updated_html = str_replace($base64, 'http://demo.com/replaced-url-' . ($index + 1), $updated_html);
    }
} else {
    echo "No base64 images found." . PHP_EOL;
}

echo PHP_EOL . PHP_EOL . PHP_EOL . PHP_EOL . PHP_EOL . PHP_EOL . "see updated html: url instead of base64";
echo PHP_EOL . $updated_html;
?>

Upvotes: 1

Mike
Mike

Reputation: 423

I use preg_match_all to capture all images in HTML document:

preg_match_all("~<img.*src\s*=\s*[\"']([^\"']+)[\"'][^>]*>~i", $body, $matches);

This one allows more relaxed syntax of declaration, with spaces and different quote types.

Regex reads like <img (any attributes like style or border) src (possible space) = (possible space) (' or ") (any non-quote symbol) (' or ") (anything until >) (>)

Upvotes: 0

Victor Oni
Victor Oni

Reputation: 379

lets assume i use

$text ='<img src="blabla.jpg" alt="blabla" />';

in

getTextBetween('src="','"',$text);

the codes will return :

blabla.jpg" alt="blabla" 

which is wrong, we want the codes to return the text between the attribute value quotes i.e attr = "value".

so

  function getTextBetween($start, $end, $text)
            {
                // explode the start string
                $first_strip= end(explode($start,$text,2));

                // explode the end string
                $final_strip = explode($end,$first_strip)[0];
                return $final_strip;
            }

does the trick!.

Try

   getTextBetween('src="','"',$text);

will return:

blabla.jpg

Thanks all the same , because your solution gave me an insight to the final solution .

Upvotes: -1

Josh
Josh

Reputation: 8149

I'm extremely late to this, but I have a simple solution not yet mentioned. Load it with simplexml_load_string (if you have simplexml enabled) and then flip it through json_encode and json_decode.

$foo = '<img class="foo bar test" title="test image" src="http://example.com/img/image.jpg" alt="test image" width="100" height="100" />';

$parsedFoo = json_decode(json_encode(simplexml_load_string($foo)), true);
var_dump($parsedFoo['@attributes']['src']); // output: "http://example.com/img/image.jpg"

$parsedFoo comes through as

array(1) {
  ["@attributes"]=>
  array(6) {
    ["class"]=>
    string(12) "foo bar test"
    ["title"]=>
    string(10) "test image"
    ["src"]=>
    string(32) "http://example.com/img/image.jpg"
    ["alt"]=>
    string(10) "test image"
    ["width"]=>
    string(3) "100"
    ["height"]=>
    string(3) "100"
  }
}

I've been using this for parsing XML and HTML for a few months now and it works pretty well. I've had no hiccups yet, though I haven't had to parse a large file with it (I imagine using json_encode and json_decode like that will get slower the larger the input gets). It's convoluted, but it's by far the easiest way to read HTML properties.

Upvotes: 4

AntonioCS
AntonioCS

Reputation: 8496

I got this code:

$dom = new DOMDocument();
$dom->loadHTML($img);
echo $dom->getElementsByTagName('img')->item(0)->getAttribute('src');

Assuming there is only one img :P

Upvotes: 9

You can go around this problem using this function:


function getTextBetween($start, $end, $text)
{
 $start_from = strpos($text, $start);
 $start_pos = $start_from + strlen($start);
 $end_pos = strpos($text, $end, $start_pos + 1);
 $subtext = substr($text, $start_pos, $end_pos);
 return $subtext;
}
$foo = '<img class="foo bar test" title="test image" src="http://example.com/img/image.jpg" alt="test image" width="100" height="100" />';
$img_src = getTextBetween('src="', '"', $foo);

Upvotes: 1

Jeff
Jeff

Reputation: 2862

Here's what I ended up doing, although I'm not sure about how efficient this is:

$imgsplit = explode('"',$data);
foreach ($imgsplit as $item) {
    if (strpos($item, 'http') !== FALSE) {
        $image = $item;
        break;
    }
}

Upvotes: 2

John Parker
John Parker

Reputation: 54445

If you don't wish to use regex (or any non-standard PHP components), a reasonable solution using the built-in DOMDocument class would be as follows:

<?php
    $doc = new DOMDocument();
    $doc->loadHTML('<img src="http://example.com/img/image.jpg" ... />');
    $imageTags = $doc->getElementsByTagName('img');

    foreach($imageTags as $tag) {
        echo $tag->getAttribute('src');
    }
?>

Upvotes: 78

karim79
karim79

Reputation: 342635

// Create DOM from string
$html = str_get_html('<img class="foo bar test" title="test image" src="http://example.com/img/image.jpg" alt="test image" width="100" height="100" />');

// echo the src attribute
echo $html->find('img', 0)->src;

http://simplehtmldom.sourceforge.net/

Upvotes: 7

St.Woland
St.Woland

Reputation: 5417

Code

<?php
    $foo = '<img class="foo bar test" title="test image" src="http://example.com/img/image.jpg" alt="test image" width="100" height="100" />';
    $array = array();
    preg_match( '/src="([^"]*)"/i', $foo, $array ) ;
    print_r( $array[1] ) ;

Output

http://example.com/img/image.jpg

Upvotes: 40

user256058
user256058

Reputation: 115

try this pattern:

'/< \s* img [^\>]* src \s* = \s* [\""\']? ( [^\""\'\s>]* )/'

Upvotes: 0

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