CODEWITHSUNDEEP
javaarrayssorting
java_doctor_101
java_doctor_101

Reputation: 3357

Sorting 2D string array in Java

I am using Arrays.Sort() function in java to sort a names in 2D array storing names and corresponding numbers. I want number to remain in the same indices as to the corresponding names. How do I do it?

Thanks in advance.

CODE

String[][] contact = new String[3][3];
contact[0][0] = "b";
contact[0][1] = "c";
contact[0][2] = "a";
contact[1][0] = "2";
contact[1][1] = "3";
contact[1][2] = "1";
Arrays.sort(contact[0]);

Example:

b c a

2 3 1

OUTPUT:

a b c

2 3 1

I want to get:

a b c

1 2 3

Upvotes: 0

Views: 119

Answers (2)

Alex - GlassEditor.com
Alex - GlassEditor.com

Reputation: 15497

Before you sort your array make a copy of it, then after sorting loop through the sorted one and use originalArray.indexOf(newArray[i]) to get the original index of the string, then set the new "index array"[i] to the value of the original index array[original index of the string].

You need to turn the original array into a list before you do this with Arrays.asList(originalArray).

Upvotes: 2

Typo
Typo

Reputation: 1900

public class MatrixCell{

 private Integer x = 0;
 private Integer y = 0;
 private String name = "";

 public MatrixCell(int x, int y, String name){
   this.x = x;
   this.y = y;
   this.name = name;
 }

 //getters and setters
}

Then make an array of MatrixCell and done. Although this way you have to make too the sort algorithm.

Upvotes: 0

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