CODEWITHSUNDEEP
javaandroidsqldatabaseandroid-edittext
otherdan
otherdan

Reputation: 71

Android: EditText returning same value as contents

The method below is responsible for inserting a new record to a database table and it is called when a button is pressed. However the String input that is assigned the value of the contents of the EditText never seems to be assigned to the new contents whenever a new value is typed in.

As a result inserting a new record only works once.

Any suggestions why this happens would be appreciated.

public void insertRecord(View additionBut) {
        System.out.println("NOW INSIDE THE INSERT RECORD");
        input = addTextInput.getText().toString();
        addTextInput.getText().clear();
        System.out.println(input);
        if (purpose.equals("ViewNovel")) {
            md.addPiece(input, "0");
        } else if (purpose.equals("ViewPlay")) {
            md.addPiece(input, "1");
        } else {
            // whatever else
        }

        displayList();
    }

Upvotes: 0

Views: 91

Answers (2)

Tabrej Khan
Tabrej Khan

Reputation: 894

Place

displayList();
addTextInput.getText().clear(); //after displayList();

May be the reference is same. Because of that when you try to clear the edit text the value in input getting reflected. If so, try creating new String object with the value in the edit text box.

Upvotes: 0

Lucifer
Lucifer

Reputation: 29662

You can also clear your EditText in another way, Try following way, 

public void insertRecord(View additionBut) {
        System.out.println("NOW INSIDE THE INSERT RECORD");
        input = addTextInput.getText().toString();
        addTextInput.setText("")                              // Change here
        System.out.println(input);
        if (purpose.equals("ViewNovel")) {
            md.addPiece(input, "0");
        } else if (purpose.equals("ViewPlay")) {
            md.addPiece(input, "1");
        } else {
            // whatever else
        }

        displayList();
    }

Upvotes: 1

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