Reputation: 171
The question is Write a program that asks the user to enter 5 different students and their mark out of 100. If the user tries to enter a student twice, the program should detect this and ask them to enter a unique student name (and their mark).
my program is..
dictionary = {}
count = 0
while count < 5:
name = raw_input("Enter your name: ")
mark = input("Enter your mark out of 100: ")
if name not in dictionary:
dictionary[name] = mark
count = count + 1
else:
name = raw_input("Enter a unique name: ")
mark = input("Enter the mark out of 100: ")
if name not in dictionary:
dictionary[name] = mark
count = count + 1
print dictionary
my problem is how do you loop the else: code if the user keeps entering the same name and mark?
Upvotes: 1
Views: 3141
Reputation: 39689
dictionary = {}
count = 0
while count < 5:
name = raw_input("Enter your name: ")
name = name.strip().lower() # store name in lower case, e.g. aamir and Aamir consider duplicate
if not dictionary.get(name):
mark = input("Enter your mark out of 100: ")
dictionary[name] = mark
count += 1
else:
print "please enter unique name"
print dictionary
aamir
and Aamir
both should be consider duplicateEnter your mark
to save one step for end userUpvotes: 1
Reputation: 1473
You mix input
and raw_input
, that's a bad thing. Usually you use raw_input
in Python 2 and input
in Python 3. The quick and dirty way to solve your problem is:
dictionary = {}
count = 0
while count < 5:
name = raw_input("Enter your name: ")
mark = raw_input("Enter your mark out of 100: ")
if name not in dictionary:
dictionary[name] = mark
count = count + 1
else:
print("You already used that name, enter an unique name.")
print dictionary
Upvotes: 1
Reputation: 579
i think you only need todo this:
dictionary = {}
count = 0
while count < 5:
name = raw_input("Enter your name: ")
mark = input("Enter your mark out of 100: ")
if name not in dictionary:
dictionary[name] = mark
count = count + 1
print dictionary
Upvotes: 0