CODEWITHSUNDEEP
node.jsbashshellinstallationenvironment-variables
A T
A T

Reputation: 13836

Bash string manipulation works differently in shell than .sh file?

I have a script to get and setup the latest NodeJS on my .deb system:

echo "Downloading, building and installing latest NodeJS"
sudo apt-get install python g++ make checkinstall
mkdir /tmp/node_build && cd $_
curl -O "http://nodejs.org/dist/node-latest.tar.gz"
tar xf node-latest.tar.gz && cd node-v*
NODE_VERSION="${PWD#*v}"
#NODE_VERSION=python -c "print '$PWD'.split('-')[-1][1:]"
echo "Installing NodeJS" $NODE_VERSION

./configure
sudo checkinstall -y --install=no --pkgversion NODE_VERSION
sudo dpkg -i node_$NODE_VERSION

Unfortunately it doesn't work; as the echo line outputs:

Installing NodeJS i8/dir-where-runnning-script-from/node-v0.10.24

It does work from the shell though:

$ cd /tmp/node_build/node-v0.10.24 && echo "${PWD#*v}"
0.10.24

Upvotes: 0

Views: 105

Answers (2)

Gordon Davisson
Gordon Davisson

Reputation: 125998

Is there another "v" in the path, like right before the "i8/"? #*v will remove through the first "v" in the variable; I'm pretty sure you want ##*v which'll remove through the last "v" in the variable. (Technically, # removes the shortest matching prefix, and ## removes the longest match). Thus:

NODE_VERSION="${PWD##*v}"

Should work.

Upvotes: 1

Reinstate Monica Please
Reinstate Monica Please

Reputation: 11603

Try this 

sudo checkinstall -y --install=no --pkgversion "${NODE_VERSION##*v}"

Upvotes: 0

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