CODEWITHSUNDEEP
cmdcygwin
Dor
Dor

Reputation: 7494

Using cygwin to netively execute cmd command and redirect stdout

Using cygwin on Windows 7, need to:

I've tried (executed in cygwin):

cmd /C "START cmd /C \"executableFileName -f -n 100 > logFilePath.txt\""

And many variations of the above line, but nothing worked.

Upvotes: 1

Views: 1016

Answers (3)

awvalenti
awvalenti

Reputation: 2013

Try one of the following:

  • start 'executableFileName -f -n 100 > logFilePath.txt'
  • cmd //c 'executableFileName -f -n 100 > logFilePath.txt'

Cygwin comes with a very interesting /usr/bin/start script, which basically calls cmd /c start [args] for you.

I found out that //c becomes /c when calling a native Windows program. Take a look at the difference:

user@pc:~ $ cmd //c echo /c //c
C:/ /c

Upvotes: 0

awvalenti
awvalenti

Reputation: 2013

If you really need cmd to run the command, I think the best you can do is:

powershell -c 'cmd /c "executableFileName -f -n 100 > logFilePath.txt"'

When calling Windows programs, cygwin translates /C to C:\ (like start /b program --> start B:\ program). This messes things up.

Since powershell accepts -c instead of /c, it works. Inside its command, you can use /c safely.

Upvotes: 0

dbenham
dbenham

Reputation: 130849

I don't have cygwin, so I cannot test. But try the following.

cmd /c start cmd /c "executableFileName -f -n 100 >logFilePath.txt"

The quotes around the command following /c are not required, so you don't need them in the first cmd /c. They are useful in the second cmd /c to prevent the redirection from activating until the final cmd is executed.

Regarding your original code - the escape character for cmd.exe is ^, not \, and you cannot escape a quote once quoting has begun. That is why I opted not to include any quotes in the outer most cmd /c

Upvotes: 1

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