CODEWITHSUNDEEP
bashgrep
Newbie
Newbie

Reputation: 3009

grep - List all lines not containing both pattern

I have a text file having some records. I have two patterns to verify and I want to list all lines from the file not containing both pattern. How can I do this using grep command?
I tried few things using grep -v but nothing seem to work.

Suppose my text file is as follows.
1. qwerpattern1yui
2. adspattern2asd
3. cczxczc
4. jkjkpattern2adsdapattern1

I want to list lines 1, 2 and 3 only.

Thanks in advance.

Upvotes: 4

Views: 9571

Answers (4)

Digital Trauma
Digital Trauma

Reputation: 16016

While the standard tools-based answers (awk, grep, etc) are generally simpler and more straightforward, for completion if you needed a pure-bash solution, you could do this:

$ while IFS= read -r ln; do [[ $ln =~ pattern1 ]] && [[ $ln =~ pattern2 ]] && continue; printf "%s\n" "$ln"; done < test 
1. qwerpattern1yui
2. adspattern2asd
3. cczxczc
$

Upvotes: 0

Jotne
Jotne

Reputation: 41460

If you like to try awk

awk '!/pattern1|pattern2/' file

It will not print any lines if it contains any of the patters

You can also expand this:

awk '!/pattern1|pattern2|pattern3|pattern4/' file

Example

cat file
one
two
three
four
one two
two
nine
six two

remove all lines with one or two or both of them.

awk '!/one|two/' file
three
four
nine

Upvotes: 3

anubhava
anubhava

Reputation: 786291

You can use:

grep -w -v -e "word1" -e "word2" file

OR else using egrep:

egrep -w -v -e "word1|word2" file

UPDATE: Based on comments, it seems following awk will work better:

awk '!(/pattern1/ && /pattern2/)' file

Upvotes: 11

Digital Trauma
Digital Trauma

Reputation: 16016

If I'm keeping up with the comments and edits right, I think this is what you need:

$ grep -E -v 'pattern1.*pattern2|pattern2.*pattern1' test
1. qwerpattern1yui
2. adspattern2asd
3. cczxczc
$

Upvotes: 3

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