Reputation: 29669
In Java, how would I get a substring of a certain character followed by a number?
The string looks like this:
To be, or not to be. (That is the question.) (243)
I want the substring up until the (243), where the number inside the parenthesis is always changing every time I call.
Upvotes: 0
Views: 580
Reputation: 166
Using a regex this can be solved with.
public class RegExParser {
public String getTextPart(String s) {
String pattern = "^(\\D+)(\\s\\(\\d+\\))$";
String part = s.replaceAll(pattern, "$1");
return part;
}
}
Simple and performance is good.
Upvotes: 0
Reputation: 423
Use a regular expression:
newstr = str.replaceFirst("\(\d+\)", "");
What this means is to find a substring beginning with (, then any number of digits, and then the character ). Then replace the substring with the empty string, "".
Reference: java.lang.String.replaceFirst()
Upvotes: 2
Reputation: 506
You could use a for loop and add the characters before the number to a separate string
String sentence = "To be, or not to be. (That is the question.) (243)";
public static void main(String[] args) {
String subSentence = getSubsentence(sentence);
}
public String getSubsentence(String sentence) {
String subSentence = "";
boolean checkForNum = false;
for (int i = 0; i < sentence.length(); i++) {
if (checkForNum) {
if (isInteger(sentence.getSubstring(i, i+1))) return subSentence;
checkForNum = false;
} else {
if (sentence.getSubstring(i, i+1).equals("(")) checkForNum = true;
else subSentence += sentence.getSubstring(i, i+1);
}
}
return subSentence;
}
public boolean isInteger(String s) {
try {
Integer.parseInt(s);
} catch(NumberFormatException e) {
return false;
}
return true;
}
Upvotes: 0
Reputation: 1241
I think you can actually just do something like:
mystring.substring(0,mystring.lastIndexOf"("))
assuming that the last thing on the line will be the number in parentheses.
Upvotes: 0
Reputation: 46219
You can use String.replaceAll()
:
String s = "To be, or not to be. (That is the question.) (243)";
String newString = s.replaceAll("\\(\\d+\\).*", "");
Upvotes: 0
Reputation: 57192
You could match it with a regex, and get the index of the regex. Then use that to get the index in the string.
An example of that is Can Java String.indexOf() handle a regular expression as a parameter?
Pattern pattern = Pattern.compile(patternStr);
Matcher matcher = pattern.matcher(inputStr);
if(matcher.find()){
System.out.println(matcher.start());//this will give you index
}
Upvotes: 0