CODEWITHSUNDEEP
phpstringarrayscontains
tarnfeld
tarnfeld

Reputation: 26556

String contains any items in an array (case insensitive)

How can i check if a $string contains any of the items expressed in an array?

$string = 'My nAmE is Tom.';
$array = array("name","tom");
if(contains($string,$array))
{
// do something to say it contains
}

Any ideas?

Upvotes: 55

Views: 85272

Answers (15)

mickmackusa
mickmackusa

Reputation: 47900

This is an ideal task to familiarize yourself with regular expressions so that you have a robust, easily adaptable, and direct script.

It is important to understand your own criteria for matching.

  1. Do you want case-insensitive matching?
  2. Do you want whole word or partial matching?
  3. Do you need to support the possibility of encountering multibyte/unicode characters?

Here is a battery of patterns that demonstrate a few likely combinations. Notice that most of the tooling is done via "pattern modifiers" after the closing pattern delimiter. The \b means a "word boundary"; if you are not familiar with this metacharacter, please invest in more research and find other posts on Stack Overflow that implement them.

Code: (Demo)

$string = 'My nAmE ïs Tom.';

// case-sensitive matching, including partial matching
$array = ['foo', 'nAmE'];
$regex[] = '#' . implode('|', array_map('preg_quote', $array)) . '#';

// case-insensitive matching, including partial matching
$array = ['foo', 'om'];
$regex[] = '#' . implode('|', array_map('preg_quote', $array)) . '#i';

// case-insensitive matching, full word matching only
$array = ['foo', 'tom'];
$regex[] = '#\b(?:' . implode('|', array_map('preg_quote', $array)) . ')\b#i';

// case-insensitive matching, full word matching only, multibyte aware
$array = ['foo', 'ïs'];
$regex[] = '#\b(?:' . implode('|', array_map('preg_quote', $array)) . ')\b#iu';


foreach ($regex as $r) {
    if (preg_match($r, $string, $m)) {
        echo "found '$m[0]' using $r on $string\n";
    } else {
        echo "no match using $r on $string\n";
    }
}

By using a delimiter which is included in preg_quote()'s list of escaped characters (e.g. #), you can simply call preg_quote by its name inside of array_map().

Upvotes: 1

Ivan Ternovtsiy
Ivan Ternovtsiy

Reputation: 119

One more workaround for contains function

function contains($string, $array, $caseSensitive = true)
{
    $strippedString = $caseSensitive ? str_replace($array, '', $string) : str_ireplace($array, '', $string);
    return $strippedString !== $string;
}

PS. as for me, I'm just using it without function...

if (str_replace($array, '', $string) !== $string) {
    // do it
}

Upvotes: 9

Pikamander2
Pikamander2

Reputation: 8299

Here's a reusable helper function that uses the PHP 8+ function str_contains:

function str_contains_any($haystack, $needles, $case_sensitive)
{
    foreach ($needles as $needle)
    {
        if (str_contains($haystack, $needle) || (($case_sensitive === false) && str_contains(strtolower($haystack), strtolower($needle))))
        {
            return true;
        }
    }
    
    return false;
}

Usage example:

$haystack = 'This is a load of shizzle';
$needles = ['fudge', 'shizzle'];
$match_found = str_contains_any($haystack, $needles, true); //true

Upvotes: 2

medilies
medilies

Reputation: 2218

/**
 * ! Only assumes that $needles strings does not contain the character '|'
 */
function contains(string $haystack, array $needles)
{
    $regex = '/' . str_replace('\|', '|', preg_quote(implode('|', $needles))) . '/i';

    return preg_match($regex, $haystack);
}

Code demo: https://3v4l.org/lY6qo#v8.1.4

Regex demo: https://www.phpliveregex.com/p/E4s

Upvotes: 0

Samee
Samee

Reputation: 67

there is easier Method

   $string = 'My nAmE is Tom.';
   $convert=explode(" ",$string,5);
   if(in_array("My", $convert)){

      echo "Ja";
   }else{

      echo "Nein";
   }

Upvotes: 0

Austyn
Austyn

Reputation: 51

I have done some testing because I needed to check user inputs against a list of words we didn't allow.

I have found that converting everything to lowercase (because my list is lowercase) and then using array intersect was by far the fastest.

    **First Option I Tested**
    $tempString= explode(' ',strtolower($string));
    $foundWords = array_intersect($tempString,$profanities);
    Time taken: 0.00065207481384277 

    **The second option I tested**
    $tempWords = explode(' ',$words);
    foreach ($tempWords as $word)
    {
        foreach ($profanities as $profanity)
        {
            if (stripos($word,$profanity) !== false) return true;
        }
    }
    Time Taken: 0.024131059646606

Upvotes: 0

MaYaNk
MaYaNk

Reputation: 429

We can check if any element of array is exists in a given string.

$string = 'My nAmE is Tom.';
$array = array("name","tom");

if(str_replace($array, '', strtolower($string)) !== strtolower($string)) {
   // If String contains an element from array      
   // Do Something
}

Upvotes: 8

Irshad Khan
Irshad Khan

Reputation: 6046

Another way to do with array_intersect() function, Try below code :

function checkString(array $arr, $str) {

  $str = preg_replace( array('/[^ \w]+/', '/\s+/'), ' ', strtolower($str) ); // Remove Special Characters and extra spaces -or- convert to LowerCase

  $matchedString = array_intersect( explode(' ', $str), $arr);

  if ( count($matchedString) > 0 ) {
    return true;
  }
  return false;
}

Upvotes: 0

Jaydeep Gondaliya
Jaydeep Gondaliya

Reputation: 331

<?php

$input = preg_quote('blu', '~'); // don't forget to quote input string!
$data = array('orange', 'blue', 'green', 'red', 'pink', 'brown', 'black');

$result = preg_grep('~' . $input . '~', $data);
print_r($result);

?>

Upvotes: 1

i.am.kk
i.am.kk

Reputation: 187

Using the accepted answer:

$string = 'My nAmE is Tom.';
$array = array("name","tom");
if(0 < count(array_intersect(array_map('strtolower', explode(' ', $string)), $array)))
{
  //do sth
}

Just a side note that the if statement could be changed to:

if(0 < count(array_intersect(explode(' ', strtolower($string)), $array)))

since it's not really necessary to use array_map to apply strtolower to each element. instead apply it to the initial string.

Upvotes: 17

jspcal
jspcal

Reputation: 51904

function contains($str, $arr)
{
  $ptn = '';
  foreach ($arr as $s) {
    if ($ptn != '') $ptn .= '|';
    $ptn .= preg_quote($s, '/');
  }
  return preg_match("/$ptn/i", $str);
}

echo contains('My nAmE is Tom', array('name', 'tom'));

Upvotes: 0

Paul Osman
Paul Osman

Reputation: 4117

Something like this would work:

$string = 'My nAmE is Tom.';
$array = array("name", "tom");
foreach ($array as $token) {
    if (stristr($string, $token) !== FALSE) {
        print "String contains: $token\n";
    }
}

Upvotes: 6

zombat
zombat

Reputation: 94167

I don't think there is a built-in function that will handle what you want. You could easily write a contains() function however:

function contains($str, array $arr)
{
    foreach($arr as $a) {
        if (stripos($str,$a) !== false) return true;
    }
    return false;
}

Upvotes: 112

TomaszSobczak
TomaszSobczak

Reputation: 2926

is that what you wanted? i hope that code is compiling :)

$string = 'My nAmE is Tom.';
$array = array("name","tom");
if(0 < count(array_intersect(array_map('strtolower', explode(' ', $string)), $array)))
{
  //do sth
}

Upvotes: 25

robertbasic
robertbasic

Reputation: 4335

Will this do the job?

$words = explode(" ", $string);
$wordsInArray = array();
foreach($words as $word) {
    if(in_array($word, $array)) {
        $wordsInArray[] = $word;
    }
}

Upvotes: 1

Related Questions