CODEWITHSUNDEEP
rubyarrays
user3214044
user3214044

Reputation: 83

Change array index to integer in ruby code

From this command, I can get array index but I can use this index as integer 

index=strInput.each_index.select{|i| strInput[i] == subInput}.map(&:to_i)
    puts (index)

When in print output, it show with bucket like [15]

And when I try to use index directly like

puts scores[index]

It return error

`[]': can't convert Array into Integer (TypeError)

How I convert index to integer.

Ps. strInput={1,2,3,4,5} / subInput={3}

Upvotes: 0

Views: 1076

Answers (1)

Arup Rakshit
Arup Rakshit

Reputation: 118271

Just do

 puts scores[index.first]

Because index is an array. Looking at your attempt it seems to me scores is also an array. Arrays are ordered, integer-indexed collections of any object. You can access the Array elements via the Integer indexes it has. But you put into it index which is an Array, not the an Integer index. So you got the error as can't convert Array into Integer (TypeError).

You could write it 

strInput.each_index.select{|i| strInput[i] == subInput}.map(&:to_i)

as

strInput.each_index.select{|i| strInput[i] == subInput}

Because you called Array#each_index, so you are passing all the Integer indices of the array strInput, to the method Array#select. Thus there is no need of the final call of the part map(&:to_i).

I would write your code as below using Array#index

ind = strInput.index { |elem| elem == subInput }    
puts scores[ind]

Upvotes: 1

Related Questions