CODEWITHSUNDEEP
jax-rsjava-ee-7jersey-client
Jason
Jason

Reputation: 12283

How do I get the URL for the request when I get a BadRequestException in Jax-rs?

I'm getting a BadRequestException when using Jersey 2 and I'd like to get the URL that was used in the request and print it in the logs when the exception is caught.

Is there a property/method combination on the BadRequestException object that will return the URL? I don't see it in the JavaDocs, but it could have a name unrelated to "URL".

Upvotes: 0

Views: 2823

Answers (1)

Michal Gajdos
Michal Gajdos

Reputation: 10379

You can't get URI from BadRequestException. But you can get it from WebTarget you invoked the request on:

WebTarget target = ClientBuilder.newClient().target("http://localhost");

try {
    String result = target.request().get(String.class);
} catch (BadRequestException bre) {
    // get the URI
    target.getUri();
}

If you don't want to use try-catch block:

Response response = target.request().get();

if (response.getStatus() == 200) {
    // OK
} else {
    // Handle other state.
}

Upvotes: 2

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