CODEWITHSUNDEEP
springspring-boot
checketts
checketts

Reputation: 14963

Spring @PropertySource using YAML

Spring Boot allows us to replace our application.properties files with YAML equivalents. However, I seem to hit a snag with my tests. If I annotate my TestConfiguration (a simple Java config), it is expecting a properties file.

For example this doesn't work: @PropertySource(value = "classpath:application-test.yml")

If I have this in my YAML file:

db:
  url: jdbc:oracle:thin:@pathToMyDb
  username: someUser
  password: fakePassword

And I'd be leveraging those values with something like this:

@Value("${db.username}") String username

However, I end up with an error like so:

Could not resolve placeholder 'db.username' in string value "${db.username}"

How can I leverage the YAML goodness in my tests as well?

Upvotes: 161

Views: 180247

Answers (21)

Rohitdev
Rohitdev

Reputation: 880

Use tool to convert from yaml to properties format. Google it there are plenty. I've been using : https://mageddo.com/tools/yaml-converter

Note : Be careful not to post sensitive data on such online tools

Upvotes: -1

Mykhaylo Adamovych
Mykhaylo Adamovych

Reputation: 20966

Using YamlPropertiesFactoryBean from spring-beans

@PropertySource(value = "my-config.yaml", factory = YamlPropertySourceFactory.class)

impl

public class YamlPropertySourceFactory implements PropertySourceFactory {

    @Override
    public PropertySource<?> createPropertySource(String name, EncodedResource encodedResource) throws IOException {
        YamlPropertiesFactoryBean factory = new YamlPropertiesFactoryBean();
        factory.setResources(encodedResource.getResource());
        return new PropertiesPropertySource(encodedResource.getResource().getFilename(), factory.getObject());
    }
}

Upvotes: 3

DJ-Glock
DJ-Glock

Reputation: 1411

Based on answer https://stackoverflow.com/a/51392715/5235756

Just for convenience, here is a kotlin version of the java code:

@PropertySource(value = ["classpath:application-test.yml"], factory = YamlPropertyLoaderFactory::class)

YamlPropertyLoaderFactory:

import org.springframework.boot.env.YamlPropertySourceLoader
import org.springframework.core.env.PropertySource
import org.springframework.core.io.support.DefaultPropertySourceFactory
import org.springframework.core.io.support.EncodedResource

class YamlPropertyLoaderFactory : DefaultPropertySourceFactory() {
    @Throws(IllegalStateException::class)
    override fun createPropertySource(name: String?, resource: EncodedResource): PropertySource<*> {
        return YamlPropertySourceLoader().load(resource.resource.filename, resource.resource).first()
    }
}

Upvotes: 0

Dave Syer
Dave Syer

Reputation: 58094

@PropertySource only supports properties files (it's a limitation from Spring, not Boot itself). Feel free to open a feature request ticket in JIRA.

UPDATE Already opened and rejected Jira requests:

Upvotes: 31

ilharp
ilharp

Reputation: 57

Here's an improved version of YamlPropertyLoaderFactory which supports the new PropertySource.ignoreResourceNotFound, based on this answer:

Java:

public final class YamlPropertyLoaderFactory extends DefaultPropertySourceFactory {
    private final YamlPropertySourceLoader yamlPropertySourceLoader = new YamlPropertySourceLoader();

    @NotNull
    public PropertySource createPropertySource(
            @Nullable String name,
            @NotNull EncodedResource resource
    ) {
        try {
            String parsedName;
            if (name != null && !name.equals(""))
                parsedName = name;
            else parsedName = resource.getResource().getFilename();
            return yamlPropertySourceLoader.load(parsedName, resource.getResource()).get(0);
        } catch (Exception e) {
            Exception possibleFileNotFoundException = ExceptionUtils.throwableOfType(e, FileNotFoundException.class);
            throw possibleFileNotFoundException != null ? possibleFileNotFoundException : e;
        }
    }
}

// Usage
@PropertySource(
   value = {"file:./my-optional-config.yml"},
   factory = YamlPropertyLoaderFactory.class,
   ignoreResourceNotFound = true
)

Kotlin:

class YamlPropertyLoaderFactory : DefaultPropertySourceFactory() {
    private val yamlPropertySourceLoader = YamlPropertySourceLoader()

    override fun createPropertySource(
        name: String?,
        resource: EncodedResource
    ): PropertySource<*> = try {
        (
            yamlPropertySourceLoader.load(
                if (name != null && name.isNotBlank()) name else resource.resource.filename,
                resource.resource
            )
            )[0]
    } catch (e: Exception) {
        throw ExceptionUtils.throwableOfType(e, FileNotFoundException::class.java) ?: e
    }
}

// Usage
@PropertySource(
    value = ["file:/my-optional-config.yml"],
    factory = YamlPropertyLoaderFactory::class,
    ignoreResourceNotFound = true
)

Upvotes: 2

Michal Foksa
Michal Foksa

Reputation: 12024

Enhancing Mateusz Balbus answer.

Modified YamlFileApplicationContextInitializer class where YAML location is defined per test class. It does not work per test, unfortunately.

public abstract class YamlFileApplicationContextInitializer
  implements ApplicationContextInitializer<ConfigurableApplicationContext> {

  /***
   * Return location of a YAML file, e.g.: classpath:file.yml
   *
   * @return YAML file location
   */
  protected abstract String getResourceLocation();

  @Override
  public void initialize(ConfigurableApplicationContext applicationContext) {
    try {
        Resource resource = applicationContext.getResource(getResourceLocation());
        YamlPropertySourceLoader sourceLoader = new YamlPropertySourceLoader();
        PropertySource<?> yamlTestProperties = sourceLoader.load("yamlTestProperties", resource, null);
        applicationContext.getEnvironment().getPropertySources().addFirst(yamlTestProperties);
    } catch (IOException e) {
        throw new RuntimeException(e);
    }
  }
}

Usage:

Create subclass of YamlFileApplicationContextInitializer with defined getResourceLocation() method and add this subclass into @SpringApplicationConfiguration annotation.

This way it is easiest to make the test class itself.

@RunWith(SpringRunner.class)
@SpringApplicationConfiguration(classes = Application.class, initializers = SimpleTest.class)
public class SimpleTest extends YamlFileApplicationContextInitializer {

  @Override
  protected String getResourceLocation() {
    return "classpath:test_specific.yml";
  }

  @Test
  public test(){
    // test your properties
  }
}

Upvotes: 0

Ishak Antony
Ishak Antony

Reputation: 79

Since Spring Boot 2.4.0 you can use ConfigDataApplicationContextInitializer as follows:

@SpringJUnitConfig(
    classes = { UserAccountPropertiesTest.TestConfig.class },
    initializers = { ConfigDataApplicationContextInitializer.class }
)
class UserAccountPropertiesTest {

    @Configuration
    @EnableConfigurationProperties(UserAccountProperties.class)
    static class TestConfig { }

    @Autowired
    UserAccountProperties userAccountProperties;

    @Test
    void getAccessTokenExpireIn() {
       assertThat(userAccountProperties.getAccessTokenExpireIn()).isEqualTo(120);
    }

    @Test
    void getRefreshTokenExpireIn() {
        assertThat(userAccountProperties.getRefreshTokenExpireIn()).isEqualTo(604800);
    }
}

See also: https://www.baeldung.com/spring-boot-testing-configurationproperties#YAML-binding

Upvotes: 7

Forest10
Forest10

Reputation: 269

enter image description here

project demo url: https://github.com/Forest10/spring-boot-family/tree/spring-boot-with-yml

I run this answer in my prod env!!! so if you against this ans. please test first!!!

There is no need to add like YamlPropertyLoaderFactory or YamlFileApplicationContextInitializer. You should convert your idea

Follow these steps:

Just add applicationContext.xml like

@ImportResource({"classpath:applicationContext.xml"})

to your ApplicationMainClass.

and your applicationContext.xml should write like this

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns:context="http://www.springframework.org/schema/context"
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  default-autowire="byName"
  xmlns="http://www.springframework.org/schema/beans"
  xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd">

  <context:property-placeholder location="classpath*:*.yml"/>
</beans>

This can help scan your application-test.yml

db:
   url: jdbc:oracle:thin:@pathToMyDb
   username: someUser
   password: fakePassword

Upvotes: 0

FedorM
FedorM

Reputation: 75

I have tried all of the listed questions, but all of them not work for my task: using specific yaml file for some unit test. In my case, it works like this:

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(initializers = {ConfigFileApplicationContextInitializer.class})
@TestPropertySource(properties = {"spring.config.location=file:../path/to/specific/config/application.yml"})
public class SomeTest {


    @Value("${my.property.value:#{null}}")
    private String value;

    @Test
    public void test() {
        System.out.println("value = " + value);
    }

}

Upvotes: 2

Betlista
Betlista

Reputation: 10549

This is not an answer to the original question, but an alternative solution for a need to have a different configuration in a test...

Instead of @PropertySource you can use -Dspring.config.additional-location=classpath:application-tests.yml.

Be aware, that suffix tests does not mean profile...

In that one YAML file one can specify multiple profiles, that can kind of inherit from each other, read more here - Property resolving for multiple Spring profiles (yaml configuration)

Then, you can specify in your test, that active profiles (using @ActiveProfiles("profile1,profile2")) are profile1,profile2 where profile2 will simply override (some, one does not need to override all) properties from profile1.

Upvotes: 0

Zhuo YING
Zhuo YING

Reputation: 1021

<dependency>
  <groupId>com.github.yingzhuo</groupId>
  <artifactId>spring-boot-stater-env</artifactId>
  <version>0.0.3</version>
</dependency>

Welcome to use my library. Now yaml, toml, hocon is supported.

Source: github.com

Upvotes: 0

Ola Sundell
Ola Sundell

Reputation: 774

Spring-boot has a helper for this, just add

@ContextConfiguration(initializers = ConfigFileApplicationContextInitializer.class)

at the top of your test classes or an abstract test superclass.

Edit: I wrote this answer five years ago. It doesn't work with recent versions of Spring Boot. This is what I do now (please translate the Kotlin to Java if necessary):

@TestPropertySource(locations=["classpath:application.yml"])
@ContextConfiguration(
        initializers=[ConfigFileApplicationContextInitializer::class]
)

is added to the top, then

    @Configuration
    open class TestConfig {

        @Bean
        open fun propertiesResolver(): PropertySourcesPlaceholderConfigurer {
            return PropertySourcesPlaceholderConfigurer()
        }
    }

to the context.

Upvotes: 71

Сергей Варюхин
Сергей Варюхин

Reputation: 665

@PropertySource can be configured by factory argument. So you can do something like:

@PropertySource(value = "classpath:application-test.yml", factory = YamlPropertyLoaderFactory.class)

Where YamlPropertyLoaderFactory is your custom property loader:

public class YamlPropertyLoaderFactory extends DefaultPropertySourceFactory {
    @Override
    public PropertySource<?> createPropertySource(String name, EncodedResource resource) throws IOException {
        if (resource == null){
            return super.createPropertySource(name, resource);
        }

        return new YamlPropertySourceLoader().load(resource.getResource().getFilename(), resource.getResource(), null);
    }
}

Inspired by https://stackoverflow.com/a/45882447/4527110

Upvotes: 54

Arunachalam Govindasamy
Arunachalam Govindasamy

Reputation: 1

Loading custom yml file with multiple profile config in Spring Boot.

1) Add the property bean with SpringBootApplication start up as follows

@SpringBootApplication
@ComponentScan({"com.example.as.*"})
public class TestApplication {

    public static void main(String[] args) {
        SpringApplication.run(TestApplication.class, args);
    }

    @Bean
    @Profile("dev")
    public PropertySourcesPlaceholderConfigurer propertiesStage() {
        return properties("dev");
    }

    @Bean
    @Profile("stage")
    public PropertySourcesPlaceholderConfigurer propertiesDev() {
        return properties("stage");
    }

    @Bean
    @Profile("default")
    public PropertySourcesPlaceholderConfigurer propertiesDefault() {
        return properties("default");

    }
   /**
    * Update custom specific yml file with profile configuration.
    * @param profile
    * @return
    */
    public static PropertySourcesPlaceholderConfigurer properties(String profile) {
       PropertySourcesPlaceholderConfigurer propertyConfig = null;
       YamlPropertiesFactoryBean yaml  = null;

       propertyConfig  = new PropertySourcesPlaceholderConfigurer();
       yaml = new YamlPropertiesFactoryBean();
       yaml.setDocumentMatchers(new SpringProfileDocumentMatcher(profile));// load profile filter.
       yaml.setResources(new ClassPathResource("env_config/test-service-config.yml"));
       propertyConfig.setProperties(yaml.getObject());
       return propertyConfig;
    }
}

2) Config the Java pojo object as follows

@Component
@JsonIgnoreProperties(ignoreUnknown = true)
@JsonInclude(Include.NON_NULL)
@ConfigurationProperties(prefix = "test-service")
public class TestConfig {

    @JsonProperty("id") 
    private  String id;

    @JsonProperty("name")
    private String name;

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }   

}

3) Create the custom yml (and place it under resource path as follows, YML File name : test-service-config.yml

Eg Config in the yml file.

test-service: 
    id: default_id
    name: Default application config
---
spring:
  profiles: dev

test-service: 
  id: dev_id
  name: dev application config

--- 
spring:
  profiles: stage

test-service: 
  id: stage_id
  name: stage application config

Upvotes: 0

balbusm
balbusm

Reputation: 1734

As it was mentioned @PropertySource doesn't load yaml file. As a workaround load the file on your own and add loaded properties to Environment.

Implemement ApplicationContextInitializer:

public class YamlFileApplicationContextInitializer implements ApplicationContextInitializer<ConfigurableApplicationContext> {
  @Override
  public void initialize(ConfigurableApplicationContext applicationContext) {
    try {
        Resource resource = applicationContext.getResource("classpath:file.yml");
        YamlPropertySourceLoader sourceLoader = new YamlPropertySourceLoader();
        PropertySource<?> yamlTestProperties = sourceLoader.load("yamlTestProperties", resource, null);
        applicationContext.getEnvironment().getPropertySources().addFirst(yamlTestProperties);
    } catch (IOException e) {
        throw new RuntimeException(e);
    }
  }
}

Add your initializer to your test:

@RunWith(SpringJUnit4ClassRunner.class)
@SpringApplicationConfiguration(classes = Application.class, initializers = YamlFileApplicationContextInitializer.class)
public class SimpleTest {
  @Test
  public test(){
    // test your properties
  }
}

Upvotes: 68

moogpwns
moogpwns

Reputation: 371

From Spring Boot 1.4, you can use the new @SpringBootTest annotation to achieve this more easily (and to simplify your integration test setup in general) by bootstrapping your integration tests using Spring Boot support.

Details on the Spring Blog.

As far as I can tell, this means you get all the benefits of Spring Boot's externalized config goodness just like in your production code, including automatically picking up YAML config from the classpath.

By default, this annotation will

... first attempt to load @Configuration from any inner-classes, and if that fails, it will search for your primary @SpringBootApplication class.

but you can specify other configuration classes if required.

For this particular case, you can combine @SpringBootTest with @ActiveProfiles( "test" ) and Spring will pick up your YAML config, provided it follows the normal Boot naming standards (i.e. application-test.yml).

@RunWith( SpringRunner.class )
@SpringBootTest
@ActiveProfiles( "test" )
public class SpringBootITest {

    @Value("${db.username}")
    private String username;

    @Autowired
    private MyBean myBean;

    ...

}

Note: SpringRunner.class is the new name for SpringJUnit4ClassRunner.class

Upvotes: 26

Doc Davluz
Doc Davluz

Reputation: 4250

Another option is to set the spring.config.location through @TestPropertySource:

@TestPropertySource(properties = { "spring.config.location = classpath:<path-to-your-yml-file>" }

Upvotes: 41

U.V.
U.V.

Reputation: 708

I needed to read some properties into my code and this works with spring-boot 1.3.0.RELEASE

@Autowired
private ConfigurableListableBeanFactory beanFactory;

// access a properties.yml file like properties
@Bean
public PropertySource properties() {
    PropertySourcesPlaceholderConfigurer propertySourcesPlaceholderConfigurer = new PropertySourcesPlaceholderConfigurer();
    YamlPropertiesFactoryBean yaml = new YamlPropertiesFactoryBean();
    yaml.setResources(new ClassPathResource("properties.yml"));
    propertySourcesPlaceholderConfigurer.setProperties(yaml.getObject());
    // properties need to be processed by beanfactory to be accessible after
    propertySourcesPlaceholderConfigurer.postProcessBeanFactory(beanFactory);
    return propertySourcesPlaceholderConfigurer.getAppliedPropertySources().get(PropertySourcesPlaceholderConfigurer.LOCAL_PROPERTIES_PROPERTY_SOURCE_NAME);
}

Upvotes: 2

Poly
Poly

Reputation: 195

I found a workaround by using @ActiveProfiles("test") and adding an application-test.yml file to src/test/resources.

It ended up looking like this:

@SpringApplicationConfiguration(classes = Application.class, initializers = ConfigFileApplicationContextInitializer.class)
@ActiveProfiles("test")
public abstract class AbstractIntegrationTest extends AbstractTransactionalJUnit4SpringContextTests {

}

The file application-test.yml just contains the properties that I want to override from application.yml (which can be found in src/main/resources).

Upvotes: 3

user2582794
user2582794

Reputation: 153

it's because you have not configure snakeyml. spring boot come with @EnableAutoConfiguration feature. there is snakeyml config too when u call this annotation..

this is my way:

@Configuration
@EnableAutoConfiguration
public class AppContextTest {
}

here is my test:

@RunWith(SpringJUnit4ClassRunner.class)
@SpringApplicationConfiguration(
        classes = {
                AppContextTest.class,
                JaxbConfiguration.class,
        }
)

public class JaxbTest {
//tests are ommited
}

Upvotes: 1

Biju Kunjummen
Biju Kunjummen

Reputation: 49915

The approach to loading the yaml properties, IMHO can be done in two ways:

a. You can put the configuration in a standard location - application.yml in the classpath root - typically src/main/resources and this yaml property should automatically get loaded by Spring boot with the flattened path name that you have mentioned.

b. The second approach is a little more extensive, basically define a class to hold your properties this way:

@ConfigurationProperties(path="classpath:/appprops.yml", name="db")
public class DbProperties {
    private String url;
    private String username;
    private String password;
...
}

So essentially this is saying that load the yaml file and populate the DbProperties class based on the root element of "db".

Now to use it in any class you will have to do this:

@EnableConfigurationProperties(DbProperties.class)
public class PropertiesUsingService {

    @Autowired private DbProperties dbProperties;

}

Either of these approaches should work for you cleanly using Spring-boot.

Upvotes: 11

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