CODEWITHSUNDEEP
java
Bob Herrmann
Bob Herrmann

Reputation: 9908

In Java, how do I dynamically determine the type of an array?

Object o = new Long[0]
System.out.println( o.getClass().isArray() )
System.out.println( o.getClass().getName() )
Class ofArray = ???

Running the first 3 lines emits;

true
[Ljava.lang.Long;

How do I get ??? to be type long? I could parse the string and do a Class.forname(), but thats grotty. What's the easy way?

Upvotes: 50

Views: 37286

Answers (3)

sakana
sakana

Reputation: 4481

Just write 

Class ofArray = o.getClass().getComponentType();

From the JavaDoc:

public Class<?> getComponentType()

Returns the Class representing the component type of an array. If this class does not represent an array class this method returns null.

Upvotes: 93

ddimitrov
ddimitrov

Reputation: 3343

http://java.sun.com/j2se/1.5.0/docs/api/java/lang/Class.html#getComponentType():

public Class<?> getComponentType()

Returns the Class representing the component type of an array. If this class does not represent an array class this method returns null...

Upvotes: 22

Daniel Spiewak
Daniel Spiewak

Reputation: 55113

@ddimitrov is the correct answer. Put into code it looks like this:

public <T> Class<T> testArray(T[] array) {
    return array.getClass().getComponentType();
}

Even more generally, we can test first to see if the type represents an array, and then get its component:

Object maybeArray = ...
Class<?> clazz = maybeArray.getClass();
if (clazz.isArray()) {
    System.out.printf("Array of type %s", clazz.getComponentType());
} else {
    System.out.println("Not an array");
}

A specific example would be applying this method to an array for which the component type is already known:

String[] arr = {"Daniel", "Chris", "Joseph"};
arr.getClass().getComponentType();              // => java.lang.String

Pretty straightforward!

Upvotes: 6

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