CODEWITHSUNDEEP
makefile
Andrew Crosland
Andrew Crosland

Reputation: 11

Why does make $(abspath path) concatenate result with current directory?

As part of a makefile recipe I have:

@echo SOMEDIR:$(SOMEDIR)
@echo abspath:$(abspath $(SOMEDIR))

Which produces:

SOMEDIR:D:/one/two/three/../../four
abspath:D:/P4_sandbox/depot/ssg/embedded/industrial/MotorControl/ReferenceDesigns/DriveOnChip_SingleIPOneEach_SoC_FFT/software/CVSX_DS5/APP_RD/D:/one/four

I expected to get:

SOMEDIR:D:/one/two/three/../../four
abspath:D:/one/four

Why is abspath concatenating its result to the value of $(CURDIR), and how do I stop it?

Upvotes: 1

Views: 12306

Answers (2)

Mischa
Mischa

Reputation: 2298

Actually, abspath is just not happy with drive-letter designations. Try it again with the D: removed. If removing D: beforehand is not possible for you, you're going to have to write a gmake macro (wrapper). Without having gmake at hand, here's an exercise in FP, defining three macros so that $(ABSPATH $(mypathvar)) works ...

_FLIP = $2 $1
_ABSPATH = $(subst \ ,:, $(strip $2 $(abspath $1)))
ABSPATH = $(_ABSPATH $(FLIP $(subst :, ,$1))))

Upvotes: 2

Etan Reisner
Etan Reisner

Reputation: 81012

That's what abspath does. It creates an absolute path. That means it must be anchored at the root. abspath is not simply canonicalize path.

You will need to subst that off or something to get the behaviour you want I imagine.

Upvotes: 1

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