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Gaurav
Gaurav

Reputation: 531

Binary String to Raw Bytes

There is a binary String :

String binaryString = "101101010111001011111000";

This string is of length 24, so it can be converted into 3 bytes.

The number that byte can contain is -128 to 127 but in the raw format it contains 8 bits.

Say : binary1 is 10110101 and binary2 is 01110010 and binary3 is 11111000

I want to convert this binaryString into raw bytes but when I am trying 

Byte.parseByte(binary1,2);

But this method convert using int and the limit of byte ranges applies.

I want to write this binaryString to the file in form of byte.

What can be the solution to have the raw byte containing 8 bits and nothing treated like number or int ?

Upvotes: 2

Views: 2147

Answers (1)

Ingo
Ingo

Reputation: 36339

The following should work:

byte theByte = (byte) Integer.parseInt("10101010", 2);

The parsed string must not be longer than 8, otherwise only the right-most 8 bits will be in the variable theByte.

Please make sure to check your output with appropriate tools (no text editors!).

Upvotes: 2

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