CODEWITHSUNDEEP
c++switch-statement
ERJAN
ERJAN

Reputation: 24500

printing inside switch , c++ , but outside of cases?

#include <stdio.h>
#include <windows.h>
#include <iostream>
using namespace std;

int main(){

    int n  ;
    cout << "insert n " <<endl ;
    cin >> n ;

    switch(n){
              cout <<"inside switch " <<endl ;
              case 2 : 
               cout << "this is 2 " <<endl ;
               break ;
              case 5 :
                cout << "this is 5 " <<endl ;
                break ;
              default :
                cout << "this is default - any number" <<endl ;
                break ;

              }

    return 0 ;

    }

Does switch structure print the cout before cases?

It does not , i checked it, is this a rule that inside switch only stuff inside cases will be printed?

Upvotes: 0

Views: 889

Answers (1)

Oliver Charlesworth
Oliver Charlesworth

Reputation: 272667

A switch is essentially just a computed goto; the individual cases are essentially just labels.

In your example code, the switch will always jump past the first cout statement.

Upvotes: 1

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