CODEWITHSUNDEEP
batch-fileif-statement
alois
alois

Reputation: 159

If Statement ( Unexpected at this time

Can't find the problem. Whenever I only input 1,an error occur. It says that ( unexpected at this time.But whenever I input other numbers as long as it has a 2 decimal places, it's okay.

@echo off
cls
    setlocal EnableDelayedExpansion
    echo|set /p= Input: 
    set /p input=
    call :process
    endlocal
    goto :EOF

:process
if %input%==0 (
    echo Input is 0
    goto :EOF
)

if %input:~-3,1%==. (
    if %input:~0,-3%==0 (
        echo Less than 1
    ) else (
        echo Greater than 1
    )
) else (
    echo Equal to 1
)
goto :EOF

Upvotes: 0

Views: 71

Answers (1)

Magoo
Magoo

Reputation: 80213

if %input:~-3,1%==. (

means if [the string from the FOURTH character of input for 1 character]==. (

When input is "1", [the string from the FOURTH character of input for 1 character] is empty, so this is interpreted as

if ==. (

The if statement expects if string1 operator string2 (dothis)

si it sees ==. as string1 and can't work out what ( means as an operator - it is expecting one of a limited set; so it complains that ( was not expected.

Cure:

if "%input:~-3,1%"=="." (

Upvotes: 1

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