CODEWITHSUNDEEP
c++c++11undefined-behavior
Khurshid
Khurshid

Reputation: 2724

Is a = 0; b = (a++, a + 1) ; undefined behavior (UB)?

see simple example:

int a = 0;
int b = (a ++  ,  a + 1); // result of b is UB or well defined ?  (c++03).

This was changed in c++11/c++14 ?

Upvotes: 22

Views: 1213

Answers (1)

CB Bailey
CB Bailey

Reputation: 791869

The result is well defined and has been since C++98. The comma operator introduces a sequence point (or a "sequenced before" relationship in later C++s) between the the write and the second read of a and I don't see any other potential reasons for undefined behavior.

Upvotes: 29

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