CODEWITHSUNDEEP
pythonloopszip
shasj
shasj

Reputation: 85

zip several files in python using loop

How can I zip multiple files using one loop in python?

I tried this but It gives me a error:

from zipfile_infolist import print_info
import zipfile
import fileinput
import glob
import os

for name in glob.glob( '*.xlsx' ):
    zf = zipfile.ZipFile('%(name)s.zip', mode='w')
    try:
        zf.write('%(name)s')
    finally:
        print 'closing'
        zf.close()
    print
    print_info('%(name)s')

This is the traceback:

Traceback (most recent call last):
  File "C:/Users/Fatt-DELL-3/ser.py", line 10, in <module>
    zf.write('%(name)s')
  File "C:\Program Files\IBM\SPSS\Statistics\22\Python\lib\zipfile.py", line 1031, in write
    st = os.stat(filename)
WindowsError: [Error 2] The system can not find the file specified: '%(name)s'

Upvotes: 2

Views: 1307

Answers (1)

Gerrat
Gerrat

Reputation: 29690

If you have a look at Python's string formatting documentation, you're using a mapping type of operation whenever your string includes something like '%(name)s. For that, you need to follow it with a mapping object like a dict, eg:

'%(name)s' % {'name':name}

You need to add this to every place where you've put '%(name)s'

So these lines:

zf = zipfile.ZipFile('%(name)s.zip', mode='w')
zf.write('%(name)s')
print_info('%(name)s')

should be written as:

zf = zipfile.ZipFile('%(name)s.zip' % {'name':name}, mode='w')
zf.write('%(name)s' % {'name':name})
print_info('%(name)s' % {'name':name})

Upvotes: 2

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