CODEWITHSUNDEEP
linuxbashunix
Nevin Thomas
Nevin Thomas

Reputation: 826

how to count number of files with a specific entry?

In my script i am using the following...

edi824Files=`find $EDI_824_FILE_DIR -name "*$ediFileDate*.edi" -a "(" -mtime -1 ")"`

here $ediFileDate should be the current date, and $EDI_824_FILE_DIR has the value like DIR/. e.g: DIR/2014-01-24

the above one is working fine, but it just pull all the files with .edi extensions. But i would like to get only the files with a specific entry. for e.g: the files which containing the value "824". how can i achieve this?

Upvotes: 1

Views: 61

Answers (2)

gromi08
gromi08

Reputation: 515

Try this:

find $EDI_824_FILE_DIR -name "*$ediFileDate*.edi" -a "(" -mtime -1 ")" -exec grep -l "824" {} \;

Upvotes: 2

Wayne Conrad
Wayne Conrad

Reputation: 108259

Pipe find through xargs and grep:

find ... | xargs grep '824'

This will list all the lines that contain "824", along with the filename and line number. If you just want the filenames, then:

find ... | xargs grep -l '824'

xargs reads from stdin. For each line read, it executes the command, passing the line as the last argument to the command.

Upvotes: 1

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