CODEWITHSUNDEEP
linuxsocketsudpbroadcast
Maksym
Maksym

Reputation: 41

Bind function in broadcast message

I am trying to send "broadcast" message from server to many clients.

Who must call bind function server or client?

Upvotes: 0

Views: 286

Answers (1)

nodakai
nodakai

Reputation: 8033

The short answer is: the clients have to issue bind(2).

Sample code in Python:

Console 1

>>> from socket import *
>>> s = socket(AF_INET, SOCK_DGRAM)
>>> s.setsockopt(SOL_SOCKET, SO_REUSEADDR, 1)
>>> s.bind(("0.0.0.0", 33440))
>>> s.recv(10000)

Console 2

>>> from socket import *
>>> s = socket(AF_INET, SOCK_DGRAM)
>>> s.setsockopt(SOL_SOCKET, SO_REUSEADDR, 1)
>>> s.bind(("0.0.0.0", 33440))
>>> s.recv(10000)

Console 3

>>> from socket import *
>>> s = socket(AF_INET, SOCK_DGRAM)
>>> s.setsockopt(SOL_SOCKET, SO_BROADCAST, 1)
>>> s.sendto("Hello world", ("127.255.255.255", 33440))
11

Then you will see 'Hello world' on Console 1 and 2.

Update

After you issue s.recv(10000) on both of Console1 and 2, you will get something like this:

$ LANG=C netstat -nu4ap | grep python
(Not all processes could be identified, non-owned process info
 will not be shown, you would have to be root to see it all.)
udp        0      0 0.0.0.0:33440           0.0.0.0:*                           31939/python
udp        0      0 0.0.0.0:33440           0.0.0.0:*                           31447/python
$ uname -a
Linux kaidev01 3.2.0-57-generic #87-Ubuntu SMP Tue Nov 12 21:35:10 UTC 2013 x86_64 x86_64 x86_64 GNU/Linux

Upvotes: 1

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