CODEWITHSUNDEEP
javastring
user3219993
user3219993

Reputation: 25

replace same words in string with one of them in java

i want to replace same words with one of them 

 "p1 p2 p2 p2 p2 p3 p3 p4 p5 p5 p5 p5 p5 p2 p2 p1 p1 p1"

to change this

 "p1 p2 p3 p4 p5 p2 p1"

is there any method in java to do this?

Upvotes: 0

Views: 80

Answers (2)

Christian Tapia
Christian Tapia

Reputation: 34146

Here is one solution:

public static void main(String[] args)
{
    String s = "p1 p2 p2 p2 p2 p3 p3 p4 p5 p5 p5 p5 p5 p2 p2 p1 p1 p1";
    String[] parts = s.split(" ");
    ArrayList<String> arr = new ArrayList<String>();

    arr.add(parts[0]); // Add first item

    for (int i = 1; i < parts.length; i++) {
        if (!parts[i - 1].equals(parts[i])) { // Check if last item is different
            arr.add(parts[i]);
        }
    }

    StringBuilder sb = new StringBuilder();

    for (String str: arr) { // Creating the new String via StringBuilder
        sb.append(str);
        sb.append(" ");
    }

    System.out.println(sb.toString());
}

Output:

p1 p2 p3 p4 p5 p2 p1

Upvotes: 1

Pshemo
Pshemo

Reputation: 124215

You can use regex.

String text = "p1 p2 p2 p2 p2 p3 p3 p4 p5 p5 p5 p5 p5 p2 p2 p1 p1 p1";
System.out.println(text.replaceAll("(\\w+)(\\s+\\1)+", "$1"));

output:

p1 p2 p3 p4 p5 p2 p1
  • (\\w+) will match single word and thanks to parenthesis it will be placed in group 1
  • in (\\s+\\1)+ \\s+ means one or more whitespace and \\1 requires same match as from group 1. Surrounding this with (...)+ requires this to exist one or more times
  • as replacement we used $1 which gets match stored in group 1 (so we are replacing many same words with first word).

Upvotes: 2

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