CODEWITHSUNDEEP
javaregexbean-validation
Francesco
Francesco

Reputation: 2382

@Pattern regex doesn't check empty values

I have an input field where a SIM number has to be entered. For that field in the bean I put the following validation expression:

@Pattern( regexp = "^(?:\\d{19})$", message = "{validation.notValidSIMNumber}" )

which should be "only 19-digit numbers are accepted".

I expected that if the field is left empty, the validation would also claim.

But instead there is no error message...

EDIT: Sorry, I wrote the false regex (with | at the end). So, to be clear: I need to validate an input field and it must be a 19-digit number. No possibility to leave it empty.

With the above regex, if I leave it empty I get no error message, but as soon as I enter something that's not a 19-digit number I get the error message.

Upvotes: 0

Views: 1946

Answers (4)

Vasyl Keretsman
Vasyl Keretsman

Reputation: 2748

The pattern ^\\d{19}$ should be enough.

Upvotes: 3

SasiRSK
SasiRSK

Reputation: 1

Hopefully, you are in need of matching 19 digit number and it too be the beginning and end of line it seems.

So for that you can use (^(\d{19})$)* - as it matches only the sentence containing 19 digits or an empty line (without any digits or characters).

Upvotes: 0

Ernestas Gruodis
Ernestas Gruodis

Reputation: 8787

Try:

System.out.println("1234567891234568977".matches("^[0-9]{19}$"));

Upvotes: 0

Sujith PS
Sujith PS

Reputation: 4864

Your Code is : ^(?:\\d{19}|)$

enter image description here

Change your code to :

@Pattern( regexp = "^(?:\\d{19})$|^$", message = "{validation.notValidSIMNumber}" )

EXPLANATION :

enter image description here

Upvotes: 0

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