CODEWITHSUNDEEP
c#javasyntaxoverridinghide
Dan Rosenstark
Dan Rosenstark

Reputation: 69787

Java Hiding: Any Way for Client Classes to Call `super`?

Aside from adding a method explicitly on the subclass to call a super method, is there anyway to "unhide" it temporarily? I would like to call the super.blah() method on a Test2 instance. Must I use a method like originalBlah, or is there another way?

public class TestingHiding {
    public static void main(String[] args) {
        Test1 b = new Test2();
        b.blah();
    }
}

class Test2 extends Test1 {
    public void blah() {
        System.out.println("test2 says blah");
    }

    public void originalBlah() {
        super.blah();
    }
}

class Test1 {
    public void blah() {
        System.out.println("test1 says blah");
    }

}

Edit: Sorry to add to the question late in the game, but I had a memory flash (I think): in C# is this different? That it depends on which class you think you have (Test1 or Test2)?

Upvotes: 2

Views: 203

Answers (4)

Jean
Jean

Reputation: 21605

Simple answer is : you can't

you could have blah be 

class Test2 extends Test1 {
    public void blah() {
        if("condition"){
            super.blah()
        }
        System.out.println("test2 says blah");
    }

}

or go the originalBlah way, or decouple the blah implementation altogether to be able to call whichever implementation you need but that's about it.

Upvotes: 1

akuhn
akuhn

Reputation: 27803

As I understand you want to do something like Test1 b = new Test2(); b.super.blah(). This cannot be done, super is strictly limited to calling from inside the subclass to the superclass.

Upvotes: 3

Michael Borgwardt
Michael Borgwardt

Reputation: 346465

No, there is no way to subvert the concept of inheritance like that.

Upvotes: 3

Mykola Golubyev
Mykola Golubyev

Reputation: 59872

It is hard to imagine situation when you need thing like this.

You can forbid method overriding.
Also you can consider Template Method pattern technique.

Upvotes: 2

Related Questions