CODEWITHSUNDEEP
pythonclassattributes
Sc4r
Sc4r

Reputation: 700

Initializes a class with n-nested tuples

In python is there a way to initialize a class with n-nested tuples? with x being 0 to n and y being an empty list.

What I mean is:

Suppose you have a class such as:

class NestedTuples:
    def __init__(self, tuple):
        self.tuple = ?

so if you were to do something like:

t = NestedTuples(4)

it will create: 

((0, []), (1, []), (2, []), (3, []))

Upvotes: 0

Views: 96

Answers (3)

zhangxaochen
zhangxaochen

Reputation: 34047

In [74]: class NestedTuples:
    ...:     def __init__(self, n):
    ...:         self.tuple = tuple((i, []) for i in range(n))
    ...:         

In [75]: t = NestedTuples(4)

In [76]: t.tuple
Out[76]: ((0, []), (1, []), (2, []), (3, []))

Upvotes: 1

user2555451
user2555451

Reputation:

This works*:

class NestedTuples:
    def __init__(self, num):
        self.tuple = tuple((x, []) for x in range(num))

See a demonstration below:

>>> class NestedTuples:
...     def __init__(self, num):
...         self.tuple = tuple((x, []) for x in range(num))
...
>>> t = NestedTuples(4)
>>> t.tuple
((0, []), (1, []), (2, []), (3, []))
>>>

Lastly, here is a reference on generator expressions.

*Note: I had to rename the tuple parameter of NestedTuples.__init__. You should never create a variable that has the same name as one of the built-ins. Doing so will overshadow it.

Upvotes: 2

Kobi K
Kobi K

Reputation: 7929

Simple code:

param = 4
nestedTuple = tuple([(i,[]) for i in range(param)])
print nestedTuple

Output:

((0, []), (1, []), (2, []), (3, []))

Upvotes: 1

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