CODEWITHSUNDEEP
c++variadic-templatesvariadic-functions
Thibaut
Thibaut

Reputation: 133

Variadic variable initialization for variadic template

I have a templated class A in which I want to call a templated function from another class B

the header looks like :

template<typename... T> class A
{
public:
    A();
    void get(type_X params);
private:
    B b_;
};

and the .hxx :

template<typename... T> void A<T...>::get(type_X params)
{
    /*here lies my problem*/
    T... variable; // just like we would do string s;
                   // and pass it to a function f(string& s) to assign it
    b_.get(params, variable...);
    /* do something with updated value of variable */
}

where member b_ (class B) has a templated function get which looks like

template<typename... T> int B<T...>::get(type_X params, const T&... variable)
{
    /* change variable, just like we would assign a new value to a string& */
    return 0; 
}

And I have no idea how to initialize (if possible) my "T..." object to be given as argument to templated function B::get.

Thanks for your help

Upvotes: 3

Views: 2312

Answers (3)

Jarod42
Jarod42

Reputation: 217283

Following may help you:

#if 1 // Not in C++11
// Helper class to be able to use expansion of std::get<Index>(tuple)
template <int... Is> struct index_sequence {};

// Following create index_sequence<0, 1, 2, .., sizeof...(Is) - 1>
template <int Index, int... Is>
struct make_index_sequence { // recursively build a sequence of indices
    typedef typename make_index_sequence<Index - 1, Index -1, Is...>::type type;
};

template <int... Is>
struct make_index_sequence<0, Is...> { // stop the recursion when 0 is reached
    typedef index_sequence<Is...> type;
};
#endif

template<typename... Ts> class A
{
public:
    void get(type_X params)
    {
        std::tuple<Ts...> t;
        a.get(params, t, make_index_sequence<sizeof...(Ts)>());
    }
private:
    template<std::size_t ... Is>
    void get(type_X params, std::tuple<Ts...>& t, index_sequence<Is...>)
    {
        b_.get(params, std::get<Is>(t)...);
    }

private:
    B b_;
};

Upvotes: 0

Sebastian Redl
Sebastian Redl

Reputation: 71989

First off, this is invalid syntax:

T... variable;

To do something like this, you need to create a tuple:

std::tuple<T...> variable;

And then you use one of the techniques to call a function with the tuple members as parameters:

"unpacking" a tuple to call a matching function pointer Pass tuple's content as variadic function arguments How do I expand a tuple into variadic template function's arguments?

Upvotes: 1

jrok
jrok

Reputation: 55395

First off, the indices machinery to create a pack of integral indices at compile time:

template< std::size_t... Ns >
struct indices {
    typedef indices< Ns..., sizeof...( Ns ) > next;
};

template< std::size_t N >
struct make_indices {
    typedef typename make_indices< N - 1 >::type::next type;
};

template<>
struct make_indices< 0 > {
    typedef indices<> type;
};

Now, you can create an array of objects:

T vars[] = { T()... };

Next, you need a helper function to create a context where you can deduce the pack of integers. Something like this:

template<typename... T, T, size_t... I>
int helper(type_X params, T* arr, indices<I...>)
{
    return b_.get(params, arr[I]...);
}

For arr parameter you'd pass the array vars you created previously and for the last one you pass make_indices<sizeof...(T)>::type().

Hope that helps.

Upvotes: 3

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