CODEWITHSUNDEEP
c#
NoviceToDotNet
NoviceToDotNet

Reputation: 10815

How to convert a string value to int so that it does not skip the preceding 0?

I have this value in a string

string FinalValue=" 0XXXXXXXXX";

which i need to fetch in integer value.

But when i convert it like below

 custNUmber = int.Parse(FinalValue);

it says value was either too large or too small for an int32. c#

and when i use long it skips the first digit 0.

Upvotes: 1

Views: 384

Answers (3)

Dmitrii Bychenko
Dmitrii Bychenko

Reputation: 186823

Maths says that 07894204661 == 7894204661 that's why resulting long is always 7894204661; if you want to restore leading zeros when converting long back to String (e.g. in order to show it in a TextBox, print out to Console etc.) you can use formatting:

  String FinalValue=" 07894204661";
  long custNUmber = long.Parse(FinalValue.Trim());

  // 11 digits wanted; "07894204661" is the outcome
  String value = custNUmber.ToString("D11");

P.S. int.MaxValue == 2147483647 only; that is the cause of the exception when you try to convert "07894204661" into int.

Upvotes: 6

Tim Schmelter
Tim Schmelter

Reputation: 460268

A leading zero is not part of an integer at all. Actually 0123==123 yields true.

So you could convert it to long first to handle the case that it's a numeric value that is simply to large (f.e. for logging purposes):

int custNUmber;
long l;
if(long.TryParse(FinalValue, out l))
{
    if(l < int.MinValue || l > int.MaxValue)
    {
        // log
    }
    else
    {
        custNUmber = (int)l;
    }
}
else
{
    // not a number
}

Upvotes: 2

Ted Bigham
Ted Bigham

Reputation: 4348

using long is the right thing to do. The zero isn't part of the number so it's supposed to skip it. I'd worry about the leading space. You might need to trim that off before parsing it.

custNUmber = long.Parse(FinalValue.trim());

Upvotes: 0

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