Reputation: 7779
What is the most efficient way to do this?
Upvotes: 54
Views: 76969
Reputation: 4453
You need only convert a value hex (in parts) to decimal and vice-versa. Also need considered, what value in hex may contains 6 or 3 characters (without character '#').
Implementation on the Python 3.5
"""Utils for working with colors."""
import textwrap
def rgb_to_hex(value1, value2, value3):
"""
Convert RGB value (as three numbers each ranges from 0 to 255) to hex format.
>>> rgb_to_hex(235, 244, 66)
'#EBF442'
>>> rgb_to_hex(56, 28, 26)
'#381C1A'
>>> rgb_to_hex(255, 255, 255)
'#FFFFFF'
>>> rgb_to_hex(0, 0, 0)
'#000000'
>>> rgb_to_hex(203, 244, 66)
'#CBF442'
>>> rgb_to_hex(53, 17, 8)
'#351108'
"""
for value in (value1, value2, value3):
if not 0 <= value <= 255:
raise ValueError('Value each slider must be ranges from 0 to 255')
return '#{0:02X}{1:02X}{2:02X}'.format(value1, value2, value3)
def hex_to_rgb(value):
"""
Convert color`s value in hex format to RGB format.
>>> hex_to_rgb('fff')
(255, 255, 255)
>>> hex_to_rgb('ffffff')
(255, 255, 255)
>>> hex_to_rgb('#EBF442')
(235, 244, 66)
>>> hex_to_rgb('#000000')
(0, 0, 0)
>>> hex_to_rgb('#000')
(0, 0, 0)
>>> hex_to_rgb('#54433f')
(84, 67, 63)
>>> hex_to_rgb('#f7efed')
(247, 239, 237)
>>> hex_to_rgb('#191616')
(25, 22, 22)
"""
if value[0] == '#':
value = value[1:]
len_value = len(value)
if len_value not in [3, 6]:
raise ValueError('Incorect a value hex {}'.format(value))
if len_value == 3:
value = ''.join(i * 2 for i in value)
return tuple(int(i, 16) for i in textwrap.wrap(value, 2))
if __name__ == '__main__':
import doctest
doctest.testmod()
Implementation on the JavaScript (adapted to the NodeJS with a support ES6)
const assert = require('assert');
/**
* Return a color`s value in the hex format by passed the RGB format.
* @param {integer} value1 An value in ranges from 0 to 255
* @param {integer} value2 An value in ranges from 0 to 255
* @param {integer} value3 An value in ranges from 0 to 255
* @return {string} A color`s value in the hex format
*/
const RGBtoHex = (value1, value2, value3) => {
const values = [value1, value2, value3];
let result = '#';
for (let i = 0; i < 3; i += 1) {
// validation input
if (values[i] < 0 || values[i] > 255) throw new Error('An each value of RGB format must be ranges from 0 to 255');
// append to result values as hex with at least width 2
result += (('0' + values[i].toString(16)).slice(-2));
}
return result.toUpperCase();
};
/**
* Convert a value from the hex format to RGB and return as an array
* @param {int} value A color`s value in the hex format
* @return {array} Array values of the RGB format
*/
const hexToRGB = (value) => {
let val = value;
val = (value[0] === '#') ? value.slice(1) : value;
if ([3, 6].indexOf(val.length) === -1) throw new Error(`Incorect a value of the hex format: ${value}`);
if (val.length === 3) val = val.split('').map(item => item.repeat(2)).join('');
return val.match(/.{2}/g).map(item => parseInt(`0x${item}`, 16));
};
assert.deepEqual(hexToRGB('fff'), [255, 255, 255]);
assert.deepEqual(hexToRGB('#fff'), [255, 255, 255]);
assert.deepEqual(hexToRGB('#000000'), [0, 0, 0]);
assert.deepEqual(hexToRGB('000000'), [0, 0, 0]);
assert.deepEqual(hexToRGB('#d7dee8'), [215, 222, 232]);
assert.deepEqual(hexToRGB('#1E2F49'), [30, 47, 73]);
assert.deepEqual(hexToRGB('#030914'), [3, 9, 20]);
assert.equal(RGBtoHex(255, 255, 255), '#FFFFFF');
assert.equal(RGBtoHex(0, 0, 0), '#000000');
assert.equal(RGBtoHex(96, 102, 112), '#606670');
assert.equal(RGBtoHex(199, 204, 214), '#C7CCD6');
assert.equal(RGBtoHex(22, 99, 224), '#1663E0');
assert.equal(RGBtoHex(0, 8, 20), '#000814');
module.exports.RGBtoHex = RGBtoHex;
module.exports.hexToRGB = hexToRGB;
Implementation on the C (intended for the C11 standart)
// a type for a struct of RGB color
typedef struct _ColorRGB {
unsigned short int red;
unsigned short int green;
unsigned short int blue;
} colorRGB_t;
/*
Convert a color`s value from the hex format to the RGB.
Return -1 if a passed value in the hex format is not correct, otherwise - return 0;
*/
static int
convertColorHexToRGB(const char originValue[], colorRGB_t *colorRGB) {
// a full value of color in hex format must constains 6 charapters
char completedValue[6];
size_t lenOriginValue;
size_t lenCompletedValue;
// an intermediary variable for keeping value in the hex format
char hexSingleValue[3];
// a temp pointer to char, need only to the strtol()
char *ptr;
// a variable for keeping a converted number in the hex to the decimal format
long int number;
// validation input
lenOriginValue = strlen(originValue);
if (lenOriginValue > 7 || lenOriginValue < 3) return -1;
// copy value without sign '#', if found as first in the string
(originValue[0] == '#') ? strcpy(completedValue, originValue + 1) : strcpy(completedValue, originValue);
lenCompletedValue = strlen(completedValue);
// if the value has only 3 charapters, dublicate an each after itself
// but if not full version of the hex name of a color (6 charapters), return -1
if (lenCompletedValue == 3) {
completedValue[5] = completedValue[2];
completedValue[4] = completedValue[2];
completedValue[3] = completedValue[1];
completedValue[2] = completedValue[1];
completedValue[1] = completedValue[0];
} else if (lenCompletedValue != 6) return -1;
// convert string, by parts, to decimal values and keep it in a struct
sprintf(hexSingleValue, "%c%c", completedValue[0], completedValue[1]);
number = strtol(hexSingleValue, &ptr, 16);
colorRGB->red = number;
sprintf(hexSingleValue, "%c%c", completedValue[2], completedValue[3]);
number = strtol(hexSingleValue, &ptr, 16);
colorRGB->green = number;
sprintf(hexSingleValue, "%c%c", completedValue[4], completedValue[5]);
number = strtol(hexSingleValue, &ptr, 16);
colorRGB->blue = number;
return 0;
}
/*
Convert a color`s value from the RGB format to the hex
*/
static int
convertColorRGBToHex(const colorRGB_t *colorRGB, char value[8]) {
sprintf(value, "#%02X%02X%02X", colorRGB->red, colorRGB->green, colorRGB->blue);
return 0;
}
/*
Forming a string representation data in an instance of the structure colorRGB_t
*/
static int
getRGBasString(const colorRGB_t *colorRGB, char str[18]) {
sprintf(str, "rgb(%d, %d, %d)", colorRGB->red, colorRGB->green, colorRGB->blue);
return 0;
}
int main (int argv, char **argc)
{
char str[18];
char hex[8];
colorRGB_t *colorRGB_;
colorRGB_ = (colorRGB_t *)malloc(sizeof(colorRGB_));
convertColorHexToRGB("fff", colorRGB_);
getRGBasString(colorRGB_, str);
printf("Hex 'fff' to RGB %s\n", str);
convertColorRGBToHex(colorRGB_, hex);
printf("RGB %s to hex '%s'\n", str, hex);
convertColorHexToRGB("000000", colorRGB_);
getRGBasString(colorRGB_, str);
printf("Hex '000000' to RGB %s\n", str);
convertColorRGBToHex(colorRGB_, hex);
printf("RGB %s to hex '%s'\n", str, hex);
convertColorHexToRGB("#000000", colorRGB_);
getRGBasString(colorRGB_, str);
printf("Hex '#000000' to RGB %s\n", str);
convertColorRGBToHex(colorRGB_, hex);
printf("RGB %s to hex '%s'\n", str, hex);
convertColorHexToRGB("#FFF", colorRGB_);
getRGBasString(colorRGB_, str);
printf("Hex '#FFF' to RGB %s\n", str);
convertColorRGBToHex(colorRGB_, hex);
printf("RGB %s to hex '%s'\n", str, hex);
free(colorRGB_);
}
A result after compilation (I am used the GCC)
Hex 'fff' to RGB rgb(255, 255, 255)
RGB rgb(255, 255, 255) to hex '#FFFFFF'
Hex '000000' to RGB rgb(0, 0, 0)
RGB rgb(0, 0, 0) to hex '#000000'
Hex '#000000' to RGB rgb(0, 0, 0)
RGB rgb(0, 0, 0) to hex '#000000'
Hex '#FFF' to RGB rgb(255, 255, 255)
RGB rgb(255, 255, 255) to hex '#FFFFFF'
Upvotes: 3
Reputation: 27416
In python:
def hex_to_rgb(value):
"""Return (red, green, blue) for the color given as #rrggbb."""
value = value.lstrip('#')
lv = len(value)
return tuple(int(value[i:i + lv // 3], 16) for i in range(0, lv, lv // 3))
def rgb_to_hex(red, green, blue):
"""Return color as #rrggbb for the given color values."""
return '#%02x%02x%02x' % (red, green, blue)
hex_to_rgb("#ffffff") #==> (255, 255, 255)
hex_to_rgb("#ffffffffffff") #==> (65535, 65535, 65535)
rgb_to_hex(255, 255, 255) #==> '#ffffff'
rgb_to_hex(65535, 65535, 65535) #==> '#ffffffffffff'
Upvotes: 180
Reputation: 2208
Very Simple and Short implementation:
color_in_hex = 'FF00EE64' # Green Color
print('RGB =', tuple(int(color_in_hex[i:i+2], 16) for i in (0, 2, 4)))
Upvotes: 1
Reputation: 1026
In python conversion between hex and 'rgb' is also included in the plotting package matplotlib
. Namely
import matplotlib.colors as colors
Then
colors.hex2color('#ffffff') #==> (1.0, 1.0, 1.0)
colors.rgb2hex((1.0, 1.0, 1.0)) #==> '#ffffff'
The caveat is that rgb values in colors are assumed to be between 0.0 and 1.0. If you want to go between 0 and 255 you need to do a small conversion. Specifically,
def hex_to_rgb(hex_string):
rgb = colors.hex2color(hex_string)
return tuple([int(255*x) for x in rgb])
def rgb_to_hex(rgb_tuple):
return colors.rgb2hex([1.0*x/255 for x in rgb_tuple])
The other note is that colors.hex2color
only accepts valid hex color strings.
Upvotes: 43
Reputation: 163
This is a fragment of code I created for my own use in c++11. you can send hex values or strings:
void Color::SetColor(string color) {
// try catch will be necessary if your string is not sanitized before calling this function.
SetColor(std::stoul(color, nullptr, 16));
}
void Color::SetColor(uint32_t number) {
B = number & 0xFF;
number>>= 8;
G = number & 0xFF;
number>>= 8;
R = number & 0xFF;
}
// ex:
SetColor("ffffff");
SetColor(0xFFFFFF);
Upvotes: 1
Reputation: 176635
A hex value is just RGB numbers represented in hexadecimal. So you just have to take each pair of hex digits and convert them to decimal.
Example:
#FF6400 = RGB(0xFF, 0x64, 0x00) = RGB(255, 100, 0)
Upvotes: 2
Reputation: 14642
just real quick:
int r = ( hexcolor >> 16 ) & 0xFF;
int g = ( hexcolor >> 8 ) & 0xFF;
int b = hexcolor & 0xFF;
int hexcolor = (r << 16) + (g << 8) + b;
Upvotes: 19
Reputation: 3300
Modifying Jeremy's python answer to handle short CSS rgb values like 0, #999, and #fff (which browsers would render as black, medium grey, and white):
def hex_to_rgb(value):
value = value.lstrip('#')
lv = len(value)
if lv == 1:
v = int(value, 16)*17
return v, v, v
if lv == 3:
return tuple(int(value[i:i+1], 16)*17 for i in range(0, 3))
return tuple(int(value[i:i+lv/3], 16) for i in range(0, lv, lv/3))
Upvotes: 7
Reputation: 11
#!/usr/bin/env python import re import sys def hex_to_rgb(value): value = value.lstrip('#') lv = len(value) return tuple(int(value[i:i+lv/3], 16) for i in range(0, lv, lv/3)) def rgb_to_hex(rgb): rgb = eval(rgb) r = rgb[0] g = rgb[1] b = rgb[2] return '#%02X%02X%02X' % (r,g,b) def main(): color = raw_input("HEX [#FFFFFF] or RGB [255, 255, 255] value (no value quits program): ") while color: if re.search('\#[a-fA-F0-9][a-fA-F0-9][a-fA-F0-9][a-fA-F0-9][a-fA-F0-9][a-fA-F0-9]', color): converted = hex_to_rgb(color) print converted elif re.search('[0-9]{1,3}, [0-9]{1,3}, [0-9]{1,3}', color): converted = rgb_to_hex(color) print converted elif color == '': sys.exit(0) else: print 'You didn\'t enter a valid value!' color = raw_input("HEX [#FFFFFF] or RGB [255, 255, 255] value (no value quits program): ") if __name__ == '__main__': main()
Upvotes: 1
Reputation: 7315
Real answer: Depends on what kind of hexadecimal color value you are looking for (e.g. 565, 555, 888, 8888, etc), the amount of alpha bits, the actual color distribution (rgb vs bgr...) and a ton of other variables.
Here's a generic algorithm for most RGB values using C++ templates (straight from ScummVM).
template<class T>
uint32 RGBToColor(uint8 r, uint8 g, uint8 b) {
return T::kAlphaMask |
(((r << T::kRedShift) >> (8 - T::kRedBits)) & T::kRedMask) |
(((g << T::kGreenShift) >> (8 - T::kGreenBits)) & T::kGreenMask) |
(((b << T::kBlueShift) >> (8 - T::kBlueBits)) & T::kBlueMask);
}
Here's a sample color struct for 565 (the standard format for 16 bit colors):
template<>
struct ColorMasks<565> {
enum {
highBits = 0xF7DEF7DE,
lowBits = 0x08210821,
qhighBits = 0xE79CE79C,
qlowBits = 0x18631863,
kBytesPerPixel = 2,
kAlphaBits = 0,
kRedBits = 5,
kGreenBits = 6,
kBlueBits = 5,
kAlphaShift = kRedBits+kGreenBits+kBlueBits,
kRedShift = kGreenBits+kBlueBits,
kGreenShift = kBlueBits,
kBlueShift = 0,
kAlphaMask = ((1 << kAlphaBits) - 1) << kAlphaShift,
kRedMask = ((1 << kRedBits) - 1) << kRedShift,
kGreenMask = ((1 << kGreenBits) - 1) << kGreenShift,
kBlueMask = ((1 << kBlueBits) - 1) << kBlueShift,
kRedBlueMask = kRedMask | kBlueMask
};
};
Upvotes: 10