CODEWITHSUNDEEP
command-linestatisticsaveragemean
Anthony
Anthony

Reputation: 1366

What's the quickest way to get the mean of a set of numbers from the command line?

Using any tools which you would expect to find on a nix system (in fact, if you want, msdos is also fine too), what is the easiest/fastest way to calculate the mean of a set of numbers, assuming you have them one per line in a stream or file?

Upvotes: 13

Views: 2135

Answers (8)

american-ninja-warrior
american-ninja-warrior

Reputation: 8185

Ruby one liner

cat numbers.txt | ruby -ne 'BEGIN{$sum=0}; $sum=$sum+$_.to_f; END{puts $sum/$.}'

source

Upvotes: 0

user2747481
user2747481

Reputation: 611

Using "st" (https://github.com/nferraz/st):

$ st numbers.txt
N      min   max    sum    mean  sd
10.00  1.00  10.00  55.00  5.50  3.03

Specify an option to see individual stats:

$ st numbers.txt --mean
5.5

(DISCLAIMER: I wrote this tool :))

Upvotes: 2

Knox
Knox

Reputation: 2919

In Powershell, it would be

get-content .\meanNumbers.txt | measure-object -average

Of course, that's the verbose syntax. If you typed it using aliases,

gc .\meanNumbers.txt | measure-object -a

Upvotes: 1

Adam Liss
Adam Liss

Reputation: 48290

awk ' { n += $1 }; END { print n / NR }'

This accumulates the sum in n, then divides by the number of items (NR = Number of Records).

Works for integers or reals.

Upvotes: 17

Andru Luvisi
Andru Luvisi

Reputation: 25318

Awk

awk '{total += $1; count++ } END {print total/count}'

Upvotes: 14

Mitch Wheat
Mitch Wheat

Reputation: 300549

Using Num-Utils for UNIX:

average 1 2 3 4 5 6 7 8 9

Upvotes: 5

Robert Gamble
Robert Gamble

Reputation: 109022

perl -e 'while (<>) { $sum += $_; $count++ } print $sum / $count, "\n"';

Upvotes: 3

Paul Nathan
Paul Nathan

Reputation: 40309

Perl.

@a = <STDIN>;

for($i = 0; $i < #@a; $i++)
{
   $sum += $a[i];
}

print $a[i]/#@a;

Caveat Emptor: My syntax may be a little whiffly.

Upvotes: 0

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