CODEWITHSUNDEEP
scalaparsingcombinators
ademartini
ademartini

Reputation: 1441

Scala Combinator Parser not working with spaces

Why does this simple example of a scala combinator parser fail?

def test: Parser[String] = "&lt; " ~> ident <~ " &gt;"

When I provide the following string:

"&lt; a &gt;"

I get this error:

[1.8] failure: ` &gt;' expected but `&' found

&lt; a &gt;
       ^

Why is it tripping up on the space?

Upvotes: 0

Views: 131

Answers (1)

ghik
ghik

Reputation: 10764

You are probably using RegexParsers. In documentation, you can find that:

The parsing methods call the method skipWhitespace (defaults to true) and, if true, skip any whitespace before each parser is called.

To change this:

object MyParsers extends RegexParsers {
  override def skipWhitespace = false

  //your parsers...
}

Upvotes: 2

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