CODEWITHSUNDEEP
windowsbashshelldiff
Gabriel
Gabriel

Reputation: 67

Bash Shell Script: Diff command conflicting line format

I am using Windows OS.

My program:

#!/bin/bash

    OIFS="$IFS"
    IFS=$'\n'

    find teste1 -type f | while read -r firstResult

    do

      find teste2 -type f | while read -r secondResult

       do

        firstName=${firstResult##*[/|\\]}
        secondName=${secondResult##*[/|\\]}

         if [[ "$( echo "$firstName" | tr [A-Z] [a-z])" == "$( echo "$secondName" | tr [A-Z] [a-z])" ]]; then
          echo "$firstResult" "$secondResult" >> equal
         else
          echo "$firstResult" "$secondResult" >> notEqual
         fi

         if [[ $firstName == $secondName ]]; then
          echo "$firstResult" "$secondResult" >> equal2
         fi

       done

    done

    diff -2 "--line-format=%L" "--unchanged-line-format=" equal equal2 > renamedFiles.lst

    rm equal
    rm equal2
    rm notEqual

Whenever I run this program, it says "diff: conflicting line format". However, it produces the "renamedFiles.lst" and produces exactly the way I want. So, why is it giving me this answer? Can I fix it? It doesn't really affect my program but no one likes seeing warnings / errors on their programs, right? :)

Upvotes: 0

Views: 420

Answers (1)

l0b0
l0b0

Reputation: 58788

I think it's because you are using both --line-format (to format all lines) and --unchanged-line-format (to format unchanged lines). I guess diff doesn't define what to do if it gets conflicting format specifiers, so it fails and tells you about it. What you could do is use for example --old-line-format=%L --new-line-format=%L --unchanged-line-format=

Upvotes: 1

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