CODEWITHSUNDEEP
sqlcountlogicrowwhere-clause
Jonny
Jonny

Reputation: 97

SQL where clause count for individual records

my sql is a bit rusty (not really that great to begin with!)

I'm trying to write a query that searches through a single table, now within this table there are numerous customers buying some item. Now obviously I can search by the customer, as in 

select * from purchases where customer_name "Brian" and product_name like 'Al%;

My problem is what I'm wanting to do is, in a query like that, I want to list all the customer names that have purchased like 'Al%' and the count.

So "Alcohol", etc, would only ever be once per record in the data. But say "Brian" purchases alcohol, all day breakfast, alcohol (all in separate records). I would want to count those, so my return would be "Brian 3".

My final failed attempt was below (not sure it will help!)

select purchases.customer_name, COUNT(purchases.product_name like 'Al%') As Al purchases from purchases;

Thanks in advance. It may be something very simple and I'm totally messing it up in my head!

Upvotes: 0

Views: 280

Answers (2)

user3256554
user3256554

Reputation: 56

You forgot to add GROUP BY 

select purchases.customer_name, purchases.product_name, COUNT(purchases.product_name) from purchases where customer_name "Brian" and product_name like 'Al% GROUP BY purchases.product_name, purchases.customer_name;

You will get

Brian, Alcohol, 2

Brian, Alcohol Jin, 3

Upvotes: 3

pankeel
pankeel

Reputation: 1148

Write This Way::

That Can Solve Your Problem.

select purchases.customer_name, COUNT(purchases.product_name) As Al from purchases where purchases.product_name like 'Al%' Group by purchases.product_name;

Upvotes: 0

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