CODEWITHSUNDEEP
javaregex
Jainendra
Jainendra

Reputation: 25143

Remove substring between two characters

How can I remove substring between two characters(+ and @). Ex-

[email protected] should give [email protected]

Which regex I should use for this.

Upvotes: 0

Views: 1063

Answers (8)

Suriya Prakash.T
Suriya Prakash.T

Reputation: 11

public static string RemoveSpecialCharacters(string input) {
  Regex r = new Regex("(?:[^a-z0-9 ]|(?<=['\"])s)", RegexOptions.IgnoreCase | RegexOptions.CultureInvariant | RegexOptions.Compiled);
  return r.Replace(input, String.Empty);
}

Upvotes: -1

Mr. Polywhirl
Mr. Polywhirl

Reputation: 48610

Just write a utility class to slice Strings:

public class MyStringUtils {
    public static void main (String[] args) {
        String str = "[email protected]";
        int startIndex = str.indexOf('+');
        int endIndex = str.indexOf('@');

        System.out.println("Outer: " + sliceRangeOuter(str, startIndex, endIndex));
        System.out.println("Inner: " + sliceRangeInner(str, startIndex, endIndex));
    }

    public static String sliceStart(String str, int startIndex) {
        if (startIndex < 0)
            startIndex = str.length() + startIndex;
        return str.substring(startIndex);
    }

    public static String sliceEnd(String str, int endIndex) {
        if (endIndex < 0)
            endIndex = str.length() + endIndex;
        return str.substring(0, endIndex);
    }

    public static String sliceRangeInner(String str, int startIndex, int endIndex) {
        if (startIndex < 0)
            startIndex = str.length() + startIndex;
        if (endIndex < 0)
            endIndex = str.length() + endIndex;
        return str.substring(startIndex, endIndex);
    }

    public static String sliceRangeOuter(String str, int startIndex, int endIndex) {
        if (startIndex < 0)
            startIndex = str.length() + startIndex;
        if (endIndex < 0)
            endIndex = str.length() + endIndex;
        return sliceEnd(str, startIndex) + sliceStart(str, endIndex);
    }
}

Output:

Outer: [email protected]
Inner: +12kl

Upvotes: 0

Ben Rhouma Zied
Ben Rhouma Zied

Reputation: 2603

Here is a solution using RegExp grouping.

String str = "[email protected]";
final Pattern pattern = Pattern.compile("(.+?)\\+.*@(.+?)$");
final Matcher matcher = pattern.matcher(str);
matcher.find();
System.out.println(matcher.group(1) +matcher.group(2));

Cheers

Upvotes: 0

Will
Will

Reputation: 75625

There is no need to use a regex. You can do it just using a for loop:

for(;;) {
    int start = str.indexOf('+');
    if(start == -1) break;
    int stop = str.indexOf('@');
    if(stop == -1) break;
    str = str.substring(0,start+1) + str.substring(stop);
}

This is more verbose, but may explain better to others maintaining the code later what it is you meant to do. Not everyone is comfortable decoding regex.

Upvotes: 1

anubhava
anubhava

Reputation: 785156

Using regex it is:

String repl = str.replaceAll("(.*?)[+].*?(@.*)", "$1$2");

Though you can completely avoid regex and use String#indexOf methods to find 2 positions and get substrings using that.

Upvotes: 1

Madhura
Madhura

Reputation: 589

s = s.replace(s.substring(s.indexOf("+"), s.indexOf("@")), "");

Upvotes: 1

peter.petrov
peter.petrov

Reputation: 39457

Try this one.

str = str.replaceAll("\\+[^@]*@", "@");

class Test {

    public static void main(String[] args) {
        String str = "bunny+12kddddd+++ddd/d/d/d/d\\####[email protected]";
        str = str.replaceAll("\\+[^@]*@", "@");
        System.out.println(str);        
    }

}

Upvotes: 2

assylias
assylias

Reputation: 328608

String s = "[email protected]";
String email = s.replaceAll("\\+.*@", "@");

Upvotes: 4

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