CODEWITHSUNDEEP
phpjqueryajaxforms
ziba
ziba

Reputation: 43

Submit Form and return values using HTML / JQuery / PHP

need your help for this ... My homepage have 3 divs, #Header, #Content, #Footer. All the other pages are being opened inside the #Content div. In one of those pages I have a form with two select lists and one submit button. Just want to click the button and then return another page into the #Content div, showing the values that I select before. Like this:

The origin is: 1
The destiny is: 1

But this code returns the following ...

Notice: Undefined variable: origin in ...
Notice: Undefined variable: destiny in ...

Note: This is working if I don't open the page inside the #Content div

my Html:

<form id="myform" name="myform" action="values.php" method="POST">
    <select id="origin" name="origin">
        <option value="0" selected>-- Select Origin --</option>
        <option value="1">Portugal</option></select>
    <select id="destiny" name="destiny">
        <option value="0" selected>-- Select Destiny --</option>
        <option value="1">Lisboa</option></select>
    <input id="btSubmit" name="btSubmit" type="submit" value="search!">
</form>

my Function:

$(document).ready(function(){
    $('#btSubmit').click(function(e) {
        e.preventDefault();
        var url = $('#myform').attr('action');
        var method = $('#myform').attr('method');
    $.ajax({
        type: method,
        url: url,
        data: $('#myform').serialize(),
        success: $('#content').load(url)
        });
    });
});

my values.php page:

<?php
    if(isset($_POST['origin']) || isset($_POST['destiny'])) 
    {
        $origin = $_POST['origin'];
        $destiny = $_POST['destiny'];
    }
    echo 'The origin is:' . $origin . '<br>';
    echo 'The destiny is:' . $destiny;
?>

Upvotes: 1

Views: 1901

Answers (3)

jonasnas
jonasnas

Reputation: 3580

As Andrei mentioned you have to use 

success: function (data) {
    $('#content').html(data);
}

because calling success: $('#content').load(url) triggers a new GET request. When GET request reaches php code $_POST is not set and your variables are not initialized so you get the message from php: 

Notice: Undefined variable: origin in

Upvotes: 0

Satpal
Satpal

Reputation: 133403

You should use success callback function correctly. Accept response in callback method and set it in your div

success: function (data) {
    $('#content').html(data);
}

Additionally, You should perform your operation with form submit event. 

$('form#myform').on('submit', function (e) {

instead of 

$('#btSubmit').click(function(e) {

Upvotes: 0

Andrei
Andrei

Reputation: 56688

You should not call load again - you have already called it essentially with $.ajax and received the results. So you need just display them in the content:

success: function (data) {
    $('#content').html(data);
}

Upvotes: 3

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