CODEWITHSUNDEEP
cif-statement
user3261643
user3261643

Reputation: 3

Why is my 'if' statement getting skipped?

I'm extremely new to C and need help with this question. I want to run through an array to check to see if all elements of the array are digits from 0-9. If they aren't, I want to print false and if they are, I want to print true. For some reason, my if statement is being skipped and what I have just returns false five times. Thanks!

#include <stdio.h>

int main()
{
    int array[5] = {1, 2, 3, 15, 24};
    int i;
        for (i = 0; i < 5; i++) {
            if (array[i] >= '0' && array[i] <= '9') {
            printf("True\n");
            }
        else
        {
        printf("False\n");
        }
    }
}

Upvotes: 0

Views: 142

Answers (2)

Tom Groot
Tom Groot

Reputation: 1188

Remove the '' because you are not working with a string. Instead, use this:

if (array[i] >= 0 && array[i] <= 9) {

Upvotes: 0

AntonH
AntonH

Reputation: 6437

None of the elements of the array are above '0', because '0' is 30 decimal in ASCII.

So with your example, the highest int being 24, none of the elements satisfy your if condition.

Change it to :

if (array[i] >= 0 && array[i] <= 9) {

Upvotes: 3

Related Questions