Reputation: 115
is there a mini language way for format like this?
cram a float into 9999^99 zero padded ^ is a implied decimal.
I was doing this
for x in (450.5, 50.0, 50.0043, 9999.989,0.5):
print ('{0:06}'.format(round(x,2)).replace('.','')+'000')[0:6]
but felt a little dirty afterwords... so I changed it...
I know I could rip apart the float and put it back together
for x in (450.5, 50.0, 50.0043, 9999.989,0.5, 4):
print '{0:04}{1:0<2}'.format(int(x),int(x % 1 * 100))
this did not make me feel much better.
I know what I am doing but only because I wrote it...
anyone have a great way that is concise and clear? Or is this code clear enough?
Upvotes: 3
Views: 518