CODEWITHSUNDEEP
c++arraysstruct
bogen
bogen

Reputation: 10442

how to set a int array inside a struct in c++

I have 

struct board{
    int x[3];
    int y[3];
};

// in the class PatternReader
board PatternReader::testPattern1DX() {
   struct board aBoard;
   int x[3] = { 1,1,1 };
   aBoard = x;
   return aBoard;
}

Error is "incompatible types in assignment of int *".

How do you set arrays that are inside a struct?

Upvotes: 0

Views: 2780

Answers (3)

Lother
Lother

Reputation: 1797

Add an initializer function to the board struct:

struct board
{
   int x[3];
   int y[3];

   void initX(int* values)
   {
      for(int i = 0; i < 3; i++)
         x[i] = values[i]
   }
};

Then use it:

board PatternReader::testPattern1DX() 
{
   struct board aBoard;
   int x[3] = { 1,1,1 };
   aBoard.initX(x);
   return aBoard;
}

Upvotes: 1

m24p
m24p

Reputation: 674

Your code

int x[3] = { 1,1,1 };
aBoard = x;

is creating a variable of type int* with the initial values 1,1,1. You are then trying to assign that to a variable of type board. You don't want to do that. I think you intended:

int x[3] = { 1,1,1 };
aBoard.x = x;

Note the .x at the end of aBoard. However, this is still wrong. You can't assign arrays like that. Look up "copying arrays" instead. Is there a function to copy an array in C/C++?

Honestly, I would suggest making board a class with constructors and and then you can make the constructors behave as you want, and also look into overloading assignment operators. But for now, trying copying from x to aBoard.x is probably what you want.

Upvotes: 0

David Heffernan
David Heffernan

Reputation: 613592

You cannot assign arrays. However, you can can initialize the struct:

board PatternReader::testPattern1DX() 
{
   board aBoard = { 
       {1, 1, 1}, 
       {2, 2, 2} 
   };
   return aBoard;
}

This initializes y as well as x.

Upvotes: 4

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