Reputation:
I have a list of log entries in Audit class
public class Audit
{
public DateTime TimeStamp { get; set; }
public string User { get; set; }
public string AuditType { get; set; }
}
so a list might look like this;
20140206 11:29:20 Owen Open
20140206 11:29:21 Owen Close
20140206 11:31:20 Owen Open
20140206 11:32:20 Owen Close
20140206 11:42:20 Owen Open
20140206 11:50:00 Owen Acknowledge
This gives us gaps of 1 second, 1 minute, and 40 seconds. So the longest time it was open was the middle pair for 1 minute, then it was acknowledged at 11:50. I'm looking for the date pair where it was open longes, in this case 1 min.
I know I can process the list in sequentially and find the biggest gap using a TimeSpan but I figure there is a neat LINQ way to do it maybe with groups?
UPDATE It's not pretty, but this is the logic in really expanded walk
var audits = notice.AuditEntries.Where(a => a.User == user);
DateTime? currentOpen = null;
DateTime? bestOpen = null;
DateTime? bestClose = null;
foreach (var audit in audits)
{
if (audit.AuditType == "Open")
{
if (currentOpen.HasValue) continue;
currentOpen = audit.TimeStamp;
}
if (audit.AuditType == "Close" || audit.AuditType == "Acknowledge")
{
if (currentOpen.HasValue)
{
DateTime? currentClose = audit.TimeStamp;
if (!bestOpen.HasValue)
{
bestOpen = currentOpen;
bestClose = currentClose;
}
else
{
if (bestClose.Value.Subtract(bestOpen.Value) > currentClose.Value.Subtract(currentOpen.Value))
{
bestOpen = currentOpen;
bestClose = currentClose;
}
}
currentOpen = null;
}
}
}
Upvotes: 1
Views: 139
Reputation: 460228
Not tested but should work:
var auditGaps = audits
.GroupBy(a => a.User)
.Select(g => new
{
User = g.Key,
MinOpen = g.Where(a => a.AuditType == "Open").Select(a=> a.TimeStamp).Min(),
MaxClosed = g.Where(a => a.AuditType == "Close").Select(a=> a.TimeStamp).Max(),
MaxAcknowledge = g.Where(a => a.AuditType == "Acknowledge").Select(a=> a.TimeStamp).Max()
})
.Select(x => new
{
x.User,
LargestOpenCloseGap = x.MaxClosed - x.MinOpen,
LargestOpenAcknowledgeGap = x.MaxAcknowledge - x.MinOpen
});
Upvotes: 1
Reputation: 21764
I think this will do the trick:
IEnumerable<Audit> audits = ...
var longestAuditsByUser = audits.OrderBy(a => a.Timestamp)
// group by user, since presumably we don't want to match an open from one user with a close from another
.GroupBy(a => a.User)
.Select(userAudits =>
{
// first, align each audit entry with it's index within the entries for the user
var indexedAudits = userAudits.Select((audit, index) => new { audit, index });
// create separate sequences for open and close/ack entries
var starts = indexedAudits.Where(t => t.audit.AuditType == "Open");
var ends = indexedAudits.Where(t => t.audit.AuditType == "Close" || t.audit.AuditType == "Acknowledge");
// find the "transactions" by joining starts to ends where start.index = end.index - 1
var pairings = starts.Join(ends, s => s.index, e => e.index - 1, (start, end) => new { start, end });
// find the longest such pairing with Max(). This will throw if no pairings were
// found. If that can happen, consider changing this Select() to SelectMany()
// and returning pairings.OrderByDescending(time).Take(1)
var longestPairingTime = pairings.Max(t => t.end.Timestamp - t.start.Timestamp);
return new { user = userAudits.Key, time = longestPairingTime };
});
// now that we've found the longest time for each user, we can easily find the longest
// overall time as well
var longestOverall = longestAuditsByUser.Max(t => t.time);
Upvotes: 1