CODEWITHSUNDEEP
c++
Uys of Spades
Uys of Spades

Reputation: 93

cin.get(); doesn't work when I put it in a if statement

I used cin.get() to get the program to pause and wait for user input, and it works fine. The moment I put it in an if statement, it just skips that "wait" period and continues on with the code? How can I solve this. Here is the section that is not working. 

  do
    {
        cout << "\n\n\nEnter the number of one of the following and I will explain!\n";
        cout << "1.integer  2.boolian   3.floats   4.doubles   5.character";
        cout << "\n\n[when you are done type 'done' to continue]\n\n";
        cin >> option;

        if (option = 1);
        {
            cout << "\nInteger is the variable abbreviated as 'int' this allows C++ to only";
            cout << "\nreadwhole and real numbers \n\n";
            cin.get(); //this is the part where it just skips.. it should wait
        }

    } while (var = 1);

Upvotes: 0

Views: 274

Answers (1)

Joseph Mansfield
Joseph Mansfield

Reputation: 110768

The problem is that cin >> option will extract whatever integer is in the input stream but will leave the following newline character (which is there from hitting enter after typing in the value). When you do cin.get() it is simply extracting that newline character which is already there. Like so many other questions like this, the solution is to empty the input stream after you've extracted into option:

cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');

You are also using assignment (=) where you should be comparing for equality (==).

Upvotes: 1

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