CODEWITHSUNDEEP
cprintfscanf
MichaelKettle
MichaelKettle

Reputation: 31

Printf is returning with wrong numbers inputted from scanf

I was writing some basic code to learn the printf and scanf functions, however when integer are inputted via the scanf function, the printf function returns with completely different numbers. A similar thing happens when a character is inputted, only the printf function displays a square instead. Is there a problem with the code, or is it something else?

#include <stdio.h>
int main()
{
    char letter;
    int num1,num2;
    printf("Enter any one keyboard character:  ");
    scanf("%c", &letter);
    printf("Enter any two integers separated by a space:  ");
    scanf("%d %d", &num1, &num2);

    printf("Numbers output %d and %d \n" , &num1, &num2) ;
    printf("letter input %c\n" , &letter) ;
    printf("stored at %p" , &letter) ;
    return 0;
}

Whenever any integers or character is inputted,2686680 and 2686676 are displayed in place of the integers and a filled in rectangle is displayed instead of the character.

Any help would be much appreciate, thanks!

Upvotes: 3

Views: 2429

Answers (1)

Sunil Bojanapally
Sunil Bojanapally

Reputation: 12658

&letter mean the address of variable letter is stored which the printf are correct. You should use just letter in printf arguments as,

 printf("%d\n", letter); // prints the value stored in letter

 printf("%p\n", &letter); // prints the address where letter is stored in memory

Upvotes: 4

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