CODEWITHSUNDEEP
pythondjangodictionary
Roshan
Roshan

Reputation: 1459

pythonic way to sort a SortedDict

SortedDict is a python dict with an additional attribute which uses as sorting,

sorted_dict = {
               'personnel info': {'name': 'p_info', 'priority': 1},
               'educational info': {'name': 'edu_info', 'priority': 3}
               'additional info': {'name': 'adi_info', 'priority': 2}
}
sorted_dict.keyOrder = ['personnel info', 'educational info', 'additional info']

now we can use this sorted dict in specific ordering wherever we use.

now i have to sort this dict according to priority i.e. key order should be on priority basis

>>>print sorted_dict.keyOrder
>>> ['personnel info', 'additional info', 'educational info']

any pythonic way (like sorted) to avoid forloop/function here.

note: i already have sortedDict with initial keyOrder.

Upvotes: 0

Views: 186

Answers (1)

arocks
arocks

Reputation: 2882

Extract the priority and keys and then sort based on priority i.e.

sorted_dict.keyOrder = [key[1] for key in sorted((v['priority'],k) for k,v in sorted_dict.items())]

Upvotes: 1

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