Jake Z
Jake Z

Reputation: 1133

Inverse of a matrix using numpy

I'd like to use numpy to calculate the inverse. But I'm getting an error:

'numpy.ndarry' object has no attribute I

To calculate inverse of a matrix in numpy, say matrix M, it should be simply: print M.I

Here's the code:

x = numpy.empty((3,3), dtype=int)
for comb in combinations_with_replacement(range(10), 9):
   x.flat[:] = comb
   print x.I

I'm presuming, this error occurs because x is now flat, thus 'I' command is not compatible. Is there a work around for this?

My goal is to print the INVERSE MATRIX of every possible numerical matrix combination.

Upvotes: 86

Views: 305938

Answers (5)

Pierce Aquilonen
Pierce Aquilonen

Reputation: 21

IDK if anyone already mentioned this but I want to point out that matrix_object. I and np.linalg.inv(matrix_object) don't give a true inverse. This has given me a lot of grief. It's true that for a matrix object m, np.dot(m, m.I) = an identity matrix, but np.dot(m.I, m) =/= I. Same goes for np.linalg.inv(I).

Be careful with that.

Upvotes: 2

Eric Leschinski
Eric Leschinski

Reputation: 153822

Inverse of a matrix using python and numpy:

>>> import numpy as np
>>> b = np.array([[2,3],[4,5]])
>>> np.linalg.inv(b)
array([[-2.5,  1.5],
       [ 2. , -1. ]])

Not all matrices can be inverted. For example singular matrices are not Invertable:

>>> import numpy as np
>>> b = np.array([[2,3],[4,6]])
>>> np.linalg.inv(b)

LinAlgError: Singular matrix

Solution to singular matrix problem:

try-catch the Singular Matrix exception and keep going until you find a transform that meets your prior criteria AND is also invertable.

Upvotes: 14

dagrha
dagrha

Reputation: 2559

Another way to do this is to use the numpy matrix class (rather than a numpy array) and the I attribute. For example:

>>> m = np.matrix([[2,3],[4,5]])
>>> m.I
matrix([[-2.5,  1.5],
       [ 2. , -1. ]])

Upvotes: 26

user2357112
user2357112

Reputation: 280182

The I attribute only exists on matrix objects, not ndarrays. You can use numpy.linalg.inv to invert arrays:

inverse = numpy.linalg.inv(x)

Note that the way you're generating matrices, not all of them will be invertible. You will either need to change the way you're generating matrices, or skip the ones that aren't invertible.

try:
    inverse = numpy.linalg.inv(x)
except numpy.linalg.LinAlgError:
    # Not invertible. Skip this one.
    pass
else:
    # continue with what you were doing

Also, if you want to go through all 3x3 matrices with elements drawn from [0, 10), you want the following:

for comb in itertools.product(range(10), repeat=9):

rather than combinations_with_replacement, or you'll skip matrices like

numpy.array([[0, 1, 0],
             [0, 0, 0],
             [0, 0, 0]])

Upvotes: 112

user1330052
user1330052

Reputation: 31

What about inv?

e.g.: my_inverse_array = inv(my_array)

Upvotes: 3

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