Reputation: 779
Let's say I have this program:
class Foo {
public:
unsigned int bar () {
static unsigned int counter = 0;
return counter++;
}
};
int main ()
{
Foo a;
Foo b;
}
(Of course this example makes no sense since I'd obviously declare "counter" as a private attribute, but it's just to illustrate the problem).
I'd like to know how C++ behaves in this kind of situation: will the variable "counter" in the bar() method be the same for every instance?
Upvotes: 12
Views: 6498
Reputation: 1984
Your example was a couple lines away from being something you could compile and test:
#include <iostream>
using namespace std;
class Foo {
public:
unsigned int bar () {
static unsigned int counter = 0;
return counter++;
}
};
int main ()
{
Foo a;
Foo b;
for (int i=0; i < 10; i++)
cout<<i<<". "<<a.bar()<<" / "<<b.bar()<<endl;
}
The output looks like this:
0. 1 / 0
1. 3 / 2
2. 5 / 4
3. 7 / 6
4. 9 / 8
5. 11 / 10
6. 13 / 12
7. 15 / 14
8. 17 / 16
9. 19 / 18
So yes, the counter is shared across all instances.
Upvotes: 1
Reputation: 19799
You just need to grasp two things:
Upvotes: 0
Reputation: 139711
From The C++ Programming Language (2nd edition), page 200, by Bjarne Stroustrup:
Don't use static except inside [plain] functions (§7.1.2) and classes (§10.2.4).
Upvotes: 1
Reputation: 24351
Yes, counter
will be shared across all instances of objects of type Foo
in your executable. As long as you're in a singlethreaded environment, it'll work as expected as a shared counter.
In a multithreaded environment, you'll have interesting race conditions to debug :).
Upvotes: 10
Reputation: 55467
By "be the same for every instance" you mean there will be one instance of this variable shared across each class instance, then yes, that's correct. All instances of the class will use that same variable instance.
But keep in mind that with class variables you have to take things like multi-threading into account in many cases, which is a whole different topic.
Upvotes: 2