CODEWITHSUNDEEP
sqlsql-serversql-server-2008selectjoin
Ricky
Ricky

Reputation: 2907

SQL Query - Select highest column value for table

I have the following table: 

ProductID, GroupID, Description
1          100      Blah blah
2          200      Blah blah
3          100      Blah blah
4          200      Blah blah
5          200      Blah blah
6          100      Blah blah
7          300      Blah blah
9          300      Blah blah
10         100      Blah blah

I need to run a query that gets the data for this table such that EACH GroupID is retrieved exactly once, and the top-most ProductID is chosen. Example is shown below

ProductID, GroupID, Description
10         100      Blah blah
5          200      Blah blah
9          300      Blah blah

Any thoughts on the best approach for this? The goal being that each time this query is run, it always gets the latest ProductID for each particular GroupID. There are a lot more fields in this table, but I'm simplifying it to this example which essentially illustrates the main problem I'm trying to solve

Thanks!

Upvotes: 0

Views: 734

Answers (6)

Avi Turner
Avi Turner

Reputation: 10456

For tasks such as this one, I always love using Ranking:

SELECT ProductID, GroupID, Description FROM
(
    SELECT
        t.ProductID
        ,t.GroupID
        ,t.Description    
        ,RANK() OVER (PARTITION BY t.GroupID ORDER BY t.ProductID DESC) [Rank]
    FROM MyTableName t

) RawData
WHERE RANK = 1

In general, the inner query just gives ranks for each row in the context of it's GroupID
(this is done by RANK() OVER (PARTITION BY t.GroupID ORDER BY t.ProductID DESC).

The wrapping query is just for filtering rows which have a rank of 1 i.e. where the productID is highest in the context of the specific GroupID.

You can view the results in this Fiddle demo

Upvotes: 1

har07
har07

Reputation: 89285

You can try this (not tested) :

SELECT t.ProductID, t.GroupID, t.Description
FROM MyTableName t
    INNER JOIN
        (SELECT MAX(ProductID) As ProductID, GroupID
        FROM MyTableName
        GROUP BY GroupID) as maxPerGroup
    ON maxPerGroup.ProductID = t.ProductID

SQL fiddle demo

Upvotes: 1

Purushotham
Purushotham

Reputation: 3820

Try this query

select * from products;

+-----------+---------+-------------+
| productId | groupId | description |
+-----------+---------+-------------+
|         1 |     100 | hello       |
|         2 |     200 | hello       |
|         3 |     100 | hello       |
|         4 |     200 | hello       |
|         5 |     200 | hello       |
|         6 |     100 | hello       |
|         7 |     300 | hello       |
|         8 |     300 | hello       |
|         9 |     100 | hello       |
|        10 |     200 | hello       |
+-----------+---------+-------------+

select * from products where productId in (select MAX(productId) from products group by groupId) order by groupId ASC;

+-----------+---------+-------------+
| productId | groupId | description |
+-----------+---------+-------------+
|         9 |     100 | hello       |
|        10 |     200 | hello       |
|         8 |     300 | hello       |
+-----------+---------+-------------+

Upvotes: 0

Siddique Mahsud
Siddique Mahsud

Reputation: 1453

Sorry first i cann't understand your question,so i am down Voted. Following is the edited correct and tested query.

your records:

select * from dbo.[Products]

enter image description here

Showing Distinct GroupID with top ProductID

;with cteProducts(ProductID , GroupID) AS
(
 select max(ProductID) ProductID , GroupID
 FROM dbo.Products od
 Group by GroupID 
)
SELECT p1.ProductID,p1.GroupID,p1.[Description] from Products p1
INNER JOIN cteProducts p2 on p1.ProductID=p2.ProductID
order by p1.ProductID Desc

Your required result executed here:

enter image description here

Upvotes: -1

Jayadevan
Jayadevan

Reputation: 1342

In PostgreSQL, this works. Please check in SQL Server - 

 select t.productid, t.groupid, t.description from t, (select max(productid) mp , groupid from t  group by groupid) x where t.productid=x.mp;
;
 productid | groupid | description 
-----------+---------+-------------
         5 |     200 | BLAH BLAH
         9 |     300 | BLAH BLAH
        10 |     100 | BLAH BLAH
(3 rows)

Upvotes: -1

craigmj
craigmj

Reputation: 788

You're going to want to use the OVER clause to partition the table by GroupId. This will get you a table with two columns, the productId and a rowNum. rowNum will be 1 for the highest ProductID in each GroupID. Next, you simply inner join to that table and get ProductIDs that have a rowNum of 1. More info on the OVER clause can be found here

SELECT yt1.*  
FROM yourTable yt1 
INNER JOIN  ( 
    SELECT ROW_NUMBER() OVER(PARTITION BY GroupID ORDER BY ProductId DESC) as rowNum
    , ProductID FROM yourTable 
    )yt2 
ON yt1.ProductID = yt2.ProductID 
WHERE yt2.rowNum = 1

Upvotes: 1

Related Questions