CODEWITHSUNDEEP
java
WillBro
WillBro

Reputation: 153

Error when using nextInt in Java

I'm working on a program for my classes lab and I seem to be using nextInt wrong and I was wondering if someone could help. I couldn't find a post that had an answer. The program is designed to experiment with loops in a rolling dice simulation. It it supposed to roll two dice, determine the result, and then make a tally if it's snake eyes or doubles or whatever it may be.

So I get the following error:

DiceSimulation.java:33: error: cannot find symbol
     die1Value = nextInt();
                 ^
symbol:   method nextInt()
location: class DiceSimulation

DiceSimulation.java:34: error: cannot find symbol
     die2Value = nextInt();
                 ^
symbol:   method nextInt()
location: class DiceSimulation
2 errors

This is the code I have, I'm not entirely sure how I've used nextInt wrong.

   while (count < NUMBER)
   {
     die1Value = nextInt();
     die2Value = nextInt();
     if (die1Value == die2Value)
     {
        if (die1Value == 1)
        {   
           snakeEyes += 1;
        }
        else if (die1Value == 2)
        {   
           twos += 1;
        }   
        else if (die1Value == 3)
        {   
           threes += 1;
        }   
        else if (die1Value == 4)
        {   
           fours += 1;
        }   
        else if (die1Value == 5)
        {   
           fives += 1;
        }   
        else if (die1Value == 6)
        {   
           sixes += 1;   
        }
      }
      count += 1;
   }

Upvotes: 0

Views: 190

Answers (1)

Makoto
Makoto

Reputation: 106480

Random#nextInt() is neither a static method, nor built-in - you have to have an instance of the Random class to use it.

Here's an example:

Random dice = new Random();
int die1Value = dice.nextInt(6) + 1;
int die2Value = dice.nextInt(6) + 1;

The addition of 1 there is to offset the fact that a random value with a range bound generates values between [0, n).

Upvotes: 4

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