CODEWITHSUNDEEP
javaarrays
Evan
Evan

Reputation: 880

Getting values from an array

So let's say I have an array called arr with the values &&&&.&&. I want to find the number of ampersands (&) that are after the decimal point and store the value into numDecimalDigits.

int numDecimalDigits = 0;

char[] arr = new char[7]

for (int i = 0; i < str.length(); i ++)
{
    for (int decimal = (arr[pos] = '.'); decimal <= arr.length; decimal ++)
    {
        numDecimalDigits += 1;
    }
}

I'm not sure if this is the right approach. So the outside for loop runs through each index value of the array. The inner for loop starts at the decimal, and ends at the end of the array. Every time a new value is found, numDecimalDigits is added by one. However, in my code I think numDecimalDigits is returning an incorrect value.

Upvotes: 0

Views: 64

Answers (2)

Baby
Baby

Reputation: 5092

No need to use array. It would be easy like this:(Assuming str value must contains one '.' )

    int numDecimalDigits = str.split("\\.")[1].length();

Or you can do by subtracting str.length()-1 with indexOf(".")

    int numDecimalDigits = str.length()-1 - str.indexOf(".");

Upvotes: 1

Weibo Li
Weibo Li

Reputation: 3605

You only need one loop：

boolean foundDot = false;
for (int i = 0; i < arr.length; i++) {
    if(arr[i] == '.') {
        foundDot = true;
    } else if(foundDot) {
        numDecimalDigits ++;
    }
}

Upvotes: 1

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