Reputation: 1849
TABLE X
col1,col2
1 , 2
1 , 7
1 , 4
1 , 8
2 , 3
2 , 1
2 , 2
3 , 1
3 , 8
3 , 9
3 , 4
4 , 5
4 , 3
4 , 2
4 , 8
4 , 4
I want to retrieve the col1 values that contains in the col2 the values 2 and 4 in this case it will retrieve the values 1 and 4 How can i accomplish this without using the UNION ALL operator ?
The query that i am using is
select distinct col1
from X as A
where col1 = (
select col1 from (
select distinct col1
from X as B
where A.col1 = B.col1 and col2 = 2
union ALL
select distinct col1
from X as C
where A.col1 = C.col1 and col2 = 4
) D
group by col1
having count(col1) > 1
)
It is returning the correct result but i guess is to performance expensive. Can anyone give me ideas about how to achieve the same result but without unions ?
Upvotes: 0
Views: 848
Reputation: 79929
This problem is called Relational Division, here is one way to do so:
SELECT col1
FROM tablex
WHERE col2 IN (2, 4)
GROUP BY col1
HAVING COUNT(DISTINCT col2) >=2
The HAVING COUNT(col2) >=2
will ensure that the selected col1
must have both the two values 2 and 4 at least.
Upvotes: 2
Reputation: 3477
I think the best performance will come from inner joining the table with itself:
SELECT DISTINCT X1.col1
FROM X X1 INNER JOIN X X2 ON X1.col1=X2.col1
WHERE X1.col2=2 AND X2.col2=4
Upvotes: 1