CODEWITHSUNDEEP
shellsedawk
user3294574
user3294574

Reputation: 13

Replace random text between a constant starting and ending string using shell command

How to replace random text between :50K and :53B in each line with CREDIT using shell?

The input is

{:32tyfddf:65 trfdfd :67 ghfdfd :50K:xxxxhh:53B:fg :43:fg $
{:32tyfddf:65 trfdfd :67 ghfdfd :50K:yyyyhh:53B:fg :43:fg $
{:32tyfddf:65 trfdfd :67 ghfdfd :50K:zzzzz:53B:fg :43:fg $

Upvotes: 1

Views: 4596

Answers (3)

Jotne
Jotne

Reputation: 41460

Using awk

awk -F":50K|:53B" '{$2=":50KCREDIT:53B"}8' OFS="" file
{:32tyfddf:65 trfdfd :67 ghfdfd :50KCREDIT:53B:fg :43:fg $
{:32tyfddf:65 trfdfd :67 ghfdfd :50KCREDIT:53B:fg :43:fg $
{:32tyfddf:65 trfdfd :67 ghfdfd :50KCREDIT:53B:fg :43:fg $


awk '{sub(/:50K.*:53B/,":50KCREDIT:53B")}8' file
{:32tyfddf:65 trfdfd :67 ghfdfd :50KCREDIT:53B:fg :43:fg $
{:32tyfddf:65 trfdfd :67 ghfdfd :50KCREDIT:53B:fg :43:fg $
{:32tyfddf:65 trfdfd :67 ghfdfd :50KCREDIT:53B:fg :43:fg $

gnuawk

awk '{print gensub(/(:50K).*(:53B)/,"\\1CREDIT\\2","g")}' file
{:32tyfddf:65 trfdfd :67 ghfdfd :50KCREDIT:53B:fg :43:fg $
{:32tyfddf:65 trfdfd :67 ghfdfd :50KCREDIT:53B:fg :43:fg $
{:32tyfddf:65 trfdfd :67 ghfdfd :50KCREDIT:53B:fg :43:fg $

Upvotes: 2

Michal Gasek
Michal Gasek

Reputation: 6423

Using Perl:

perl -pi.bak -e 's/(\:50K).+?(\:53B)/${1}CREDIT${2}/g;' input_file

Basic usage:

s/replace_this/with_this/g;

(\:50K) and (\:53B) in replace this part are in parenthesis because these are so called capturing groups. You can refer to these capturing groups as ${1} and ${2} (or \1 and \2) in the with_this part, CREDIT as literal replacing whatever is in between ( .+?(\:53B) - means whatever character, whatever number of occurrences until :53B appears).

: is escaped because it's a metacharacter in regex.

Backup of the file will be saved to input_file.bak

Using your input, the output is:

$ cat input_file
{:32tyfddf:65 trfdfd :67 ghfdfd :50KCREDIT:53B:fg :43:fg $
{:32tyfddf:65 trfdfd :67 ghfdfd :50KCREDIT:53B:fg :43:fg $
{:32tyfddf:65 trfdfd :67 ghfdfd :50KCREDIT:53B:fg :43:fg $

Hope it helps.

Upvotes: 1

Petr Skocik
Petr Skocik

Reputation: 60067

 sed 's/:50K.*:53B/:50KCREDIT:53B/g'

A basic sed replace expression:

s/what_to_look_for/what_to_replace_with/

g means "do it for all found patterns on the line" (you might want to skip that).

Usage: You use sed by either letting it read from stdin:

 cat path/to/your_text_file | sed 's/:50K.*:53B/:50KCREDIT:53B/g'

or by suplying the text file in which you want to replace as an argument

 sed 's/:50K.*:53B/:50KCREDIT:53B/g' path/to/your_text_file

Each will print the replace version to stdout. Neither will modify the original file in place.

Upvotes: 1

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