CODEWITHSUNDEEP
linuxbashshell
CrudeCoder
CrudeCoder

Reputation: 401

How to run a command, which executes another terminal running a script, in the backgroud

So I'm currently writing a BASH script that scans certain text files. There are thousands of text files so I wrote another script that divides up how many articles there are and distributes the load into other terminals which will then run the scanning script. My problem is that when I run my load distribution script I don't want 10 different terminals popping on my screen. Somehow I have to put these terminals in the background yet still run. I know there is a command & that supposedly allows you to do this, but the terminals still pop on my screen.

So far I have this command:

for ((i=1; i<=5; i++))
do
gnome-terminal -x ./script $a $b $c $d
done

Five terminals running ./script pop out on the screen. I want them to just run in the background and so they don't pop on the screen. Simply adding & to the end of the gnome-terminal command doesn't work. Any suggestions?

Upvotes: 1

Views: 574

Answers (2)

CrudeCoder
CrudeCoder

Reputation: 401

Thanks to epx (first person to comment the question) there is actually a very simple way to run 10 different terminals in the background:

screen -d -m ./script

if u run this in a for loop you can create multiple terminals in the background.

Upvotes: 1

Tim
Tim

Reputation: 5369

You want to use parenthesis to create a subshell:

for ((i=1; i<=5; i++))
do
    (./script $a $b $c $d)&
done

Upvotes: 0

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